Tengo dos objetos.
const arrayOne = [ { label: "Categories", to: "/categories", id: "product_type", }, { label: "Colors", to: "/colors", id: "color", }, { label: "Materials", to: "/materials", id: "material", }, { label: "Sizes", to: "/sizes", id: "sizes", }, { label: "Designers", to: "/designers", id: "designer_slug", }, { label: "Stores", to: "/stores", id: "retailer_slug", }, ]; const arrayTwo = [ { id: "gender", label: "Gender", lazy_loaded: false, }, { id: "product_type", label: "Category", lazy_loaded: false, }, { id: "quick_filters", label: "Quick filters", lazy_loaded: false, }, { id: "final_price", label: "Price", lazy_loaded: false, }, { id: "color", label: "Color", lazy_loaded: false, }, { id: "material", label: "Material", lazy_loaded: false, }, { id: "designer_slug", label: "Brand", lazy_loaded: true, }, { id: "retailer_slug", label: "Store", lazy_loaded: true, }, ];Como puede ver, ambos tienen la clave 'id'. Si los ID en arrayOne no están en arrayTwo, me gustaría que se eliminen de arrayOne (el objeto completo). Entonces, en este caso, solo el objeto con "tamaños" debe eliminarse de arrayOne. ¿Cómo haría para hacer esto? ¡Gracias por adelantado!
podrías utilizar el filter :
const newArrayOne = arrayOne.filter(x => arrayTwo.find(y => y.id === x.id))Podría usar un Set con id y filtrar la otra matriz.
const arrayOne = [{ label: "Categories", to: "/categories", id: "product_type" }, { label: "Colors", to: "/colors", id: "color" }, { label: "Materials", to: "/materials", id: "material" }, { label: "Sizes", to: "/sizes", id: "sizes" }, { label: "Designers", to: "/designers", id: "designer_slug" }, { label: "Stores", to: "/stores", id: "retailer_slug" }], arrayTwo = [{ id: "gender", label: "Gender", lazy_loaded: false }, { id: "product_type", label: "Category", lazy_loaded: false }, { id: "quick_filters", label: "Quick filters", lazy_loaded: false }, { id: "final_price", label: "Price", lazy_loaded: false }, { id: "color", label: "Color", lazy_loaded: false }, { id: "material", label: "Material", lazy_loaded: false }, { id: "designer_slug", label: "Brand", lazy_loaded: true }, { id: "retailer_slug", label: "Store", lazy_loaded: true }], two = new Set(arrayTwo.map(({ id }) => id)), result = arrayOne.filter(({ id }) => two.has(id)); console.log(result); .as-console-wrapper { max-height: 100% !important; top: 0; }