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how to sort array of objects by condition javascript

I have array of objects with properties.

I would like to sort by status, that is 15, 17 then 16 at last in javascript

For a array of objects , status having value 16

should be placed at last and rest should sort by ascending as the expected output.

How to do in javascript

var result = arrobj.filter(e=>e.details.status !== 16).sort(a, b) => a.status - b.status;

var arrobj = [
  {
    "id":1,
    "name": 'xyz',
    "details": {
    "job": 'fulltime',
    "status": 15
    }
  },
  { 
    "id":2,
    "name": 'abc',
    "details": {
    "job": 'partime',
    "status": 16
    }
  },
  { 
    "id":3,
    "name": 'zen',
    "details": {
    "job": 'fulltime',
    "status": 17
    }
  },
  { 
   "id":5,
    "name": 'abu',
    "details": {
    "job": 'fulltime',
    "status": 16
    }
  },
{ 
   "id":7,
    "name": 'john',
    "details": {
    "job": 'parttime',
    "status": 15
    }
  },
 { 
   "id":10,
    "name": 'jocob',
    "details": {
    "job": 'fulltime',
    "status": 17
    }
  }
]

Expected Output

[
  {
    "id":1,
    "name": 'xyz',
    "details": {
    "job": 'fulltime',
    "status": 15
    }
  },
 { 
   "id":7,
    "name": 'john',
    "details": {
    "job": 'parttime',
    "status": 15
    }
  },
  { 
    "id":3,
    "name": 'zen',
    "details": {
    "job": 'fulltime',
    "status": 17
    }
  },
 { 
   "id":10,
    "name": 'jocob',
    "details": {
    "job": 'fulltime',
    "status": 17
    }
  },
  { 
    "id":2,
    "name": 'abc',
    "details": {
    "job": 'partime',
    "status": 16
    }
  },
  { 
   "id":5,
    "name": 'abu',
    "details": {
    "job": 'fulltime',
    "status": 16
    }
  }
]


about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

const results = [...arrobj.filter(ob => ob.details.status !== 16).sort((a,b) => a.details.status - b.details.status), ...arrobj.filter(ob => ob.details.status === 16)]

You mean this?

about 4 years ago · Juan Pablo Isaza Denunciar

0

You had to add .status in the sort function sort() To place the object with status 16 at the end, I made an seperate array with status 16 and added on the end of the array with everything else.

var result = arrobj.filter(e=>e.details.status !== 16).sort( (a, b) => a.details.status - b.details.status);
result = result.concat(arrobj.filter(e=>e.details.status == 16));


console.log(result)
about 4 years ago · Juan Pablo Isaza Denunciar

0

From EcmaScript 2019 Array.sort is stable. This mean that you can split that complex sorting into 2 - first by status, then placing all items with status 16 in the back. Not efficient solution

arrobj.sort((first,second) => first.details.status - second.details.status)
      .sort((first, second) => (first.details.status === 16) - (second.details.status === 16));
about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
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