this is a function just increment one number into array
but the problem i interface when i put alot of numbers into array (more than 16 digits)
when i use parseInt() just returned 16 correct numbers and more than that be zero
6145390195186705000
and expected
6145390195186705543
the function
var plusOne = function(digits) {
var numbersInString = digits.join('');
var theNumbers = parseInt(numbersInString);
var theNumbersPlusOne = theNumbers + 1;
var result = String(theNumbersPlusOne).split("").map((theNumbersPlusOne) => {
return Number(theNumbersPlusOne);
});
return result;
};
console.log(plusOne([6,1,4,5,3,9,0,1,9,5,1,8,6,7,0,5,5,4,3]));You can use BigInt to handle this problem.
var plusOne = function(digits) {
var numbersInString = digits.join('');
var theNumbers = BigInt(numbersInString);
var theNumbersPlusOne = theNumbers + BigInt(1);
var result = theNumbersPlusOne.toString().split("").map((theNumbersPlusOne) => {
return Number(theNumbersPlusOne);
});
return result;
};
console.log(plusOne([6,1,4,5,3,9,0,1,9,5,1,8,6,7,0,5,5,4,3]));Just expanding on my above comment with another solution...
You've exceeded the maximum safe integer value. (Number.MAX_SAFE_INTEGER, which equals 9007199254740991). Numbers larger than this are not supported with standard integer types in javascript, or rather there's not enough precision to represent them. Anything larger than this is represented in scientific notation and the extra digits are truncated and represented only as zeroes.
With that said, you don't even need to convert the array to a string to an integer just to increment it. You can just increment the individual digits in the array, starting at the end and working your way forwards to "carry the 1" so to speak.
var plusOne = function(digits) {
for(let i = digits.length - 1; i > -1; i--)
{
if(digits[i] == 9)
{
digits[i] = 0;
if(i == 0)
digits = [1].concat(digits);
}
else
{
digits[i]++;
break;
}
}
return digits;
};
console.log(plusOne([6,1,4,5,3,9,0,1,9,5,1,8,6,7,0,5,5,4,3]));