Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

190
Vistas
How can I fade images in sequence?

How do I stop the second image from beginning to fade in until the first one has fully faded in?

let pic = $('.oya')
let pic2 = $('.oya1')

$(document).ready(function() {
  pic.hide()
  pic.fadeIn(20000);
  pic2.hide()
  pic2.fadeIn(40000);
})

let nextIndex = index + 1;

if (nextIndex < maxIndex) {
  showImg(nextIndex);
} else {
  location.reload();
}
about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

Use the fadeIn callback:

<script>
  let pic = $('.oya')
  let pic2 = $('.oya1')

  $(document).ready(function(){
    pic.hide()
    pic2.hide()

    pic.fadeIn(20000, function(){  // This function executes when fadeIn has completed
      pic2.fadeIn(40000);
    });
 });
</script>

EDIT

but what is i wanted to add more pics like pic3, pic4 and so on...

Then you need to create a recursive function that will use the fadeIn callback until there is no more images.

I made you an example where the delay for each image is stored in a data- attribute... making it really simple to use.

See comments throughout the code.

$(document).ready(function () {
  let timed = $(".timed");
  let maxIndex = timed.length;

  // The function to fade an image in, based on its index
  function showImg(index) {
    // Get the delay from the data attribute
    let delay = parseInt(timed.eq(index).data("time"));
    
    // Just in case you forget about the data-time in the HTML markup
    if (isNaN(delay)) {
      console.clear();
      console.log(`the image at index ${index} has no data-time value.`);
      return;
    }
    
    // Fading in
    console.clear();
    console.log(`Fading in image index ${index} over ${delay}ms`);
    timed.eq(index).fadeIn(delay, function () {
      
      // Using the complete callback, if there are still images to fade in,
      // have anothere recursion with the next index
      let nextIndex = index + 1;
      if (nextIndex < maxIndex) {
        showImg(nextIndex);
      } else {
        console.clear();
        console.log("Finished.");
      }
    });
  }

  // Start the first one
  showImg(0);
});
.timed{
  display: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<img class="timed" data-time="4000" src="https://via.placeholder.com/50">
<img class="timed" data-time="2000" src="https://via.placeholder.com/50">
<img class="timed" data-time="500" src="https://via.placeholder.com/50">
<img class="timed" data-time="7000" src="https://via.placeholder.com/50">
<img class="timed" data-time="3500" src="https://via.placeholder.com/50">

CodePen

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda