let array1= [
{ "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]},
{ "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]},
{ "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]}
];
const array2= ['2012'];
Result I wanted
{ "id": 100, name: "A", "details": [{"year": "2012"}]}
I know i can filter the array with this code
array1.filter(o =>
o.details.some(p=> {
return array2.includes(p.year)
})
)
But is there a way to remove the objects as well.
We can reduce to avoid multiple steps
This reduce filters and deletes part of the details array
let array1 = [
{ "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]},
{ "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]},
{ "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]}
];
const array2 = ['2012'];
let array3 = array1.reduce((acc, {id,name,details}) => {
if (array2.includes(details[0].year)) {
acc.push({ id, name, details: details[0] })
}
return acc
}, [])
console.log(array3)