Company logo
  • Empleos
  • Bootcamp
  • Acerca de nosotros
  • Para profesionales
    • Inicio
    • Empleos
    • Cursos y retos
    • Preguntas
    • Profesores
    • Bootcamp
  • Para empresas
    • Inicio
    • Nuestro proceso
    • Planes
    • Pruebas
    • Nómina
    • Blog
    • Comercial
    • Calculadora

0

64
Vistas
How to filter an array of object inside an array of objects based on an array and also remove properties of that object?
let array1= [
    { "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]},
    { "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]},
    { "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]}
];

const array2= ['2012'];

Result I wanted

{ "id": 100, name: "A", "details": [{"year": "2012"}]}

I know i can filter the array with this code

array1.filter(o => 
  o.details.some(p=> {
    return array2.includes(p.year)
  })
)

But is there a way to remove the objects as well.

7 months ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

We can reduce to avoid multiple steps

This reduce filters and deletes part of the details array

let array1 = [
    { "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]},
    { "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]},
    { "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]}
];

const array2 = ['2012'];

let array3 = array1.reduce((acc, {id,name,details}) => {
  if (array2.includes(details[0].year)) {
    acc.push({ id, name, details: details[0] })
  }
  return acc
}, [])

console.log(array3)

7 months ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos