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VistasGetting Table row ID and Values in jQuery Array
In my web application, I created a table to show some items to the table. In the table, there are nine columns and the last has an editable cell.
The first column includes the Part_Id related to the Part No record and that field is hidden. So I want to get all the Id and data that does not contain the empty values in the `New Order Qty' column and pass all values to the controller.
So on the Create Order button click event, I tried to call this function to took Id and the Order Qty and add them to an array. But only the first record is going to the array.
Is there a way to get only the records that contain values in the New Order Qty to array to pass it to the controller?
function createOrder() {
var Orders = new Array();
$("#tblParts").each(function() {
var order = {};
var partId = this.getElementsByTagName("td")[0];
var pID = partId.innerText;
var cellOrder = this.getElementsByTagName("td")[8];
var cellOrderId = cellOrder.innerText;
order.Id = pID;
order.OrderQty = cellOrderId;
Orders.push(order);
});
}
·
Juan Pablo Isaza
1 Respuestas
Responde la pregunta0
- IDs need to be unique
- You have jQuery, use it
const Orders = $("#tableId tbody tr").filter(function() {
const cells = $(this).find("td");
return cells.eq(8).text().trim() != ""
}).map(function() {
const cells = $(this).find("td");
return {
[cells.eq(0).text().trim()]: +cells.eq(8).text()
}
}).get()
console.log(Orders)<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table id="tableId">
<thead>
<tr>
<th>ID</th>
<th></th>
<th></th>
<th></th>
<th></th>
<th></th>
<th></th>
<th></th>
<th>QTY</th>
</tr>
</thead>
<tbody>
<tr>
<td>ID 1</td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td>32</td>
</tr>
<tr>
<td>ID 2</td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
</tr>
<tr>
<td>ID 3</td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td>23</td>
</tr>
</tbody>
</table>
·
Juan Pablo Isaza
Denunciar
Responde la pregunta