You have an array with a single object whose values you want to sort by a property. For that you'll want to:

1. Access the first object in the outer array with array[0]
2. Extract the values of the object as an array with Object.values
3. Sort the values in descending order with the sort function (a,b) => b.points - a.points
4. Obtain your 10 elements with .slice(0,10)

const array = [
  {
    '1485958472927784961': {
      name: 'bruno fiverr',
      points: 6,
      user_id: '1485958472927784961',
      tweets: [Array]
    },
    '1414575563323420679': {
      name: 'ju',
      points: 7,
      user_id: '1414575563323420679',
      tweets: [Array]
    }
  }
];

const top10 = Object.values(array[0]).sort((a,b) => b.points - a.points).slice(0,10);

console.log(top10);

The outermost array is useless here. I would change your data structure to an object with key-values:

const data = {
  '1485958472927784961': {
    name: 'bruno fiverr',
    points: 6,
    user_id: '1485958472927784961',
    tweets: [],
  },
  '1414575563323420679': {
    name: 'ju',
    points: 7,
    user_id: '1414575563323420679',
    tweets: [],
  },
};

From this you can just get all the values which becomes an array of the objects, then run a sort on that.

const data = {
  '1485958472927784961': {
    name: 'bruno fiverr',
    points: 6,
    user_id: '1485958472927784961',
    tweets: []
  },
  '1414575563323420679': {
    name: 'ju',
    points: 7,
    user_id: '1414575563323420679',
    tweets: []
  }
}

const sorted = Object.values(data).sort(function(a, b) {
  return a.points > b.points ? 1 : -1;
}).slice(0, 10);

console.log(sorted)