Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

216
Vistas
Add duration to DateTime in JavaScript

I have an array of dates:

dates: 
  [ { start: '30.05.2022 02:30:00', end: '30.05.2022 03:30:00' } 
  , { start: '30.05.2022 02:34:01', end:  '3.06.2022 04:34:01' } 
  ]

What I want is to make the start of the second item of an array to be the end of the first item of an array and without breaking duration. The desired result should look like this:

dates: 
  [ { start: '30.05.2022 02:30:00', end: '30.05.2022 03:30:00' } 
  , { start: '30.05.2022 03:30:00', end:  '3.06.2022 05:34:00' } 
  ] 

I've tried to implement my solution, but it gives incorrect result, because duration of momentjs exceeds 24 hours:

const dateFormat = 'DD.MM.YYYY HH:mm:ss'

const parseDateByMoment= (dateString) => {
  return moment(dateString, dateFormat)
}

const convertDateToString= (dateString) => {
  return dateString.format(dateFormat)

}

const addOrSubtractDate = (startDate, endDate, isAdding) => {
  const startDateDuration = moment.duration(startDate.format("HH:mm:ss"))
  const endDateDuration = moment.duration(endDate.format("HH:mm:ss"))
  
  const result = isAdding 
    ? endDateDuration + startDateDuration
    : endDateDuration - startDateDuration
  return moment.duration(result)
}

const formatToTime = (diff) => {
  return moment.utc(diff).format("HH:mm:ss.SSS");
}

const makeSequentialTimeInTracks = (dates) => {
    dates.forEach((aDate, index) => {
        if (index !== 0) {
      let prevEndDate = dates[index - 1].end
      prevEndDate = parseDateByMoment(prevEndDate)
      aDate.start = convertDateToString(prevEndDate)
      // console.log('aDate.start is', aDate.start)      
      
      const start = parseDateByMoment(aDate.start)
      const durationStart = moment.duration(start.format("HH:mm:ss"))
      console.log('2. aDate.start is', start)

      let end = parseDateByMoment(aDate.end)
      const durationEnd =  moment.duration(end.format("HH:mm:ss"))
      console.log('2. aDate.end is', end)

      let difference = addOrSubtractDate(start, end, false)
      difference = moment(difference)
      let durationDifference = moment.duration(difference.format("HH:mm:ss"))
      console.log('durationDifference', 
        moment.duration(durationDifference))

      const temp = start.clone()
      console.log('2. temp is', temp)
      temp.startOf('day').add(difference)
      console.log('temp', temp.format(dateFormat))
      // aDate.end = convertDateToString(addOrSubtractDate(start, difference, true))
        }
  });
  
  return dates
}


const sequantialTime = makeSequentialTime(dates)
console.log(dates)

Any soultion with pure JavaScript or momentjs library will be highly appreciated.

about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

"simply" do

const makeSequentialTime = (() => // IIFE closure 
  {
  const // ---------------------------- utilities functions
    pad = n => n > 9 ? n : '0'+n // min 2 digits
  , getDateUTC = DMY_hms =>     // date string conversion to UTC (time zone = 0)
      {
      let [D,M,Y,h,m,s] = DMY_hms.split(/\.|\s|\:/).map(Number)
      return new Date(Date.UTC(Y,--M,D,h,m,s,0))
      }
  , getDate_DMY_hms = dte =>     // UTC date conversion to DMY_hms format
      ( dte.getUTCDate()          + '.'
      + pad(dte.getUTCMonth() +1) + '.'
      + dte.getUTCFullYear()      + ' '
      + pad(dte.getUTCHours())    + ':'
      + pad(dte.getUTCMinutes())  + ':'
      + pad(dte.getUTCSeconds())
    ) ;
  return (dates) =>  // main function
    {
    let
      d0_end    = getDateUTC(dates[0].end   )  
    , d1_start  = getDateUTC(dates[1].start )
    , d1_end    = getDateUTC(dates[1].end   )
    , sDelta_d1 = Math.abs(d1_start - d1_end) / 1000
      ;
    d0_end.setSeconds(d0_end.getSeconds() + sDelta_d1)

    Object.assign( dates[1], { start: dates[0].end
                             , end: getDate_DMY_hms(d0_end) })
    }
  })();


// -------------------------------------- test :

const objX = 
  { dates: 
    [ { start: '30.05.2022 02:30:00', end: '30.05.2022 03:30:00' } 
    , { start: '30.05.2022 02:34:01', end:  '3.06.2022 04:34:01' } 
  ] }

makeSequentialTime( objX.dates )

console.log ( 'result:\n' + JSON.stringify( objX.dates ).replace('},{','}\n,{') )
.as-console-wrapper {max-height: 100% !important;top: 0;}
.as-console-row::after {display: none !important;}

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda