const small = {
a: 1,
func: function(b, c, d) {
return this.a + b + c + d;
},
};
const large = {
a: 5,
};
small.func(2, 3, 5);I need to access a: 5 from large object into small object. currently small.func(2,3,5) is giving 11 as output. I need to get 15 as ouput.
You can either use call or apply here as:
const result = small.func.call(large, 2, 3, 5);
What above statement means is that You are taking the function(or can say borrowing) small.func function and applying in the context of large object with argument 2, 3, 5.
const small = {
a: 1,
func: function(b, c, d) {
return this.a + b + c + d;
},
};
const large = {
a: 5,
};
const result = small.func.call(large, 2, 3, 5);
// const result = small.func.apply(large, [2, 3, 5]);
console.log(result);Like this-
function func(b, c, d) {
return this.a + b + c + d;
}
const small = {
a: 1,
};
const large = {
a: 5,
};
func.call(large, 2,3, 5)