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Break map loop inside return in component

I'm trying to loop into an array to create the component content, if condition on array element is not satisfied then break the loop and return 1 component

leaves.map(leave => leave.id === currentUser.id ? <div> {leave} </div> : <div> no leaves </div>)

This is the code I have so far, no leaves is printed out every time leave.id is different than currentUser's id

What I need to is, print no leaves only when none of the leaves's id matches the currentUser's id and therefore I want to break the map after printing no leaves

about 4 years ago · Juan Pablo Isaza
1 Respuestas
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0

You should use Array.prototype.some. In your case, you would pass a function to the method to check whether it satisfies your condition and use the ternary operator to render the content.

const arrWithId = [670760658, 250026214, 126834449, 987103760, 882536150, 666896331, 488576796, 186598055, 103751309, 419995457, 503676712, 487691896, 744253979, 269253696, 102370148, 237328910, 409016979, 979651614, 743486466, 445993562, 779323321, 939834768, 296731253, 925812473, 114149678];
const arrWithoutId = [123456789, 250026214, 126834449, 987103760, 882536150, 666896331, 488576796, 186598055, 103751309, 419995457, 503676712, 487691896, 744253979, 269253696, 102370148, 237328910, 409016979, 979651614, 743486466, 445993562, 779323321, 939834768, 296731253, 925812473, 114149678];
const id = 123456789;

const checker = elem => id === elem;
console.log(`With ID: ${arrWithId.some(checker) ? "yes" : "no"}`)
console.log(`Array: ${arrWithId}`);
console.log(`Without ID: ${arrWithoutId.some(checker) ? "yes" : "no"}`)
console.log(`Array: ${arrWithoutId}`);

about 4 years ago · Juan Pablo Isaza Denunciar
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