Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

233
Vistas
Socket.io HTML - Send unique content to unique clients' HTML page

I'm using NodeJS and Socket.io. I'm getting a query from the user (https://localhost:3000?id=12345) and using this query I want to send this specific user unique content. Now my problem is that all clients are getting data according to the last query from the last client. I've tried to make rooms and multiple other solutions that I've thought about or found online but with no luck.

I'm getting the query of the page like that,

app.get('/', async ({ query }, response) => { ... }

Client

$(document).ready(function () {

 socket.emit('room', key);

 socket.on('a1', function (data) {
  $("#a1").empty().append(data);
 });
 socket.on('a2', function (data) {
  $("#a2").empty().append(data);
 });
 socket.on('a3', function (data) {
  $("#a3").empty().append(data);
 });
 socket.on('a4', function (data) {
  $("#a4").empty().append(data);
 });
…

Server

io.on('connection', function (socket) {
  console.log('Connection');
  socket.removeAllListeners();
  socket.on('create', function (data) {
    console.log(`Data: ${data}`);
    socket.join(data);
    io.in(data).emit('a1', a1);
    io.in(data).emit('a2', a2);
    io.in(data).emit('a3', a3);
    io.in(data).emit('a4', a4);
  })
});
…

I really can't understand how to separate each client query from the server and then send unique content to each client without one client's content interfering with another. My initial thought was to make one room per client and send their unique content by using that room but for some reason, it's like the content is ending up in every client.

Thank you very much!

about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

Is just you turn the object used to manage the content better like this:

The clientside:

$(document).ready(function () {
    const userKey = 'unique-id-for-each-user'
    socket.emit('room', {key : key, userKey : userKey});

    //if you emit something in this channel (same as userKey) on server will get here
    socket.on(userKey, function (data) {
        if(data.key === 'a1')
            $("#a1").empty().append(data.content);
    
        if(data.key === 'a2')
            $("#a2").empty().append(data.content);
    
        if(data.key === 'a3')
            $("#a3").empty().append(data.content);
    });

    //if you emit something in this channel ('allClients') on server will get here
    socket.on('allClients', function(data) {
        if(data.key === 'a1')
            $("#a1").empty().append(data.content);
    
        if(data.key === 'a2')
            $("#a2").empty().append(data.content);
    
        if(data.key === 'a3')
            $("#a3").empty().append(data.content);      
    })
});

The serverside:

io.on('connection', function (socket) {
    console.log('Connection');
    socket.removeAllListeners();  
    socket.on('room', function (data) {
        console.log(`Data: ${data}`);

        if(data.key === 'a1')
            io.sockets.emit(data.userKey, {key : 'a1', content: a1});
        if(data.key === 'a2')
            io.sockets.emit(data.userKey, {key : 'a2', content: a2});
        if(data.key === 'a3')
            io.sockets.emit(data.userKey, {key : 'a3', content: a3});
        if(data.key === 'a4')
            io.sockets.emit(data.userKey, {key : 'a4', content: a4});
    })
});

As you see, i just change the variable you pass as parameter to give me what i need, as serverside as clientside.

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda