This is a fun one - I am building a profanity checker!
For the purposes of this exercise, let's have an array of forbidden words, like so:
const forbiddenWords = ['apples', 'oranges', 'blue carrots', 'mushy green peas'];
Then I will have an input field for a user to input the something. It could be an infinite combo of words, but I would like to find ALL instances of the forbidden words and return them as an array. I've thought of this function, which gets me really close:
const forbiddenWords = ['apples', 'oranges', 'blue carrots', 'mushy green peas'];
const userInput = 'Broccoli is my favorite food. I hate oranges and blue carrots';
const checkIfValidInput = () => {
// Will return an array that looks like: ['Broccoli', 'is', 'my', 'favorite', ...]
const splitWords = userInput.split(" ");
const array = [];
for (let i in forbiddenWords) {
if (splitWords.indexOf(forbiddenWords[i]) !== -1) {
array.push(forbiddenWords[i]);
}
}
return array.sort((x, y) => x - y);
};
Running the above will make the result of array be ['oranges', 'blue', 'carrots']. How could I build out the function to check for 'blue carrots' or 'mushy green peas' all in one? I'd like the above function to return: ['oranges', 'blue carrots'].
Thoughts?
You can use regex for this situation. This will also give you ability to match with case insensitivity
const checkIfValidInput = () => {
const forbiddenWords = ['apples', 'oranges', 'blue carrots', 'mushy green peas'];
const userInput = 'Broccoli is my favorite food. I hate oranges and blue carrots';
const result = forbiddenWords.reduce((acc, words) => {
const match = userInput.match(new RegExp(words, ['gi']))
return match ? acc.concat(match) : acc
}, [])
result.sort()
console.log(result)
}
checkIfValidInput()Also, array.sort((x, y) => x - y); is not required as the values you have are string. You can rely on array.sort() or if you really want to do manual sort, try string.localeCompare(string2)
You're probably best off creating a regular expression. This way, you can skip the next to split and ignore capitalization issues
You can do this like
var regexStr = "";
for (let i = 0; i < forbiddenWords.length; i++) {
if (i != 0) regexStr += "|";
regexStr+= "(" + forbiddenWords[i] + ")";
}
var regex = RegExp.compile(regexStr,"gim");
var matches = userInput.match(regex);
You can check the sentence with every single phrases whether it's a match or not and if it's then you can return the phrase and store in a variable.
Technically, using of filter() and includes() would resolve the task. Lemme know if it helps.
let matched = forbiddenWords.filter(phrase => {
if(userInput.includes(phrase)) return phrase;
});
return matched;