I'm trying to get to the code property of an error caught by try/catch like so:

  try {
    const { foo } = await import('./foo');
    // [...]
  } catch (error) {
    if (error instanceof Error) {
      if (error.code === 'MODULE_NOT_FOUND') {
         // [...]
      }
    }
  }

but this gives me the following compilation error:

TSError: ⨯ Unable to compile TypeScript:
src/server.ts:44:17 - error TS2339: Property 'code' does not exist on type 'Error'.

I installed @types/node@16.x.x and my tsconfig.json looks like:

{
  "extends": "@tsconfig/node16/tsconfig.json",
  "include": ["src/**/*"],
  "exclude": ["node_modules", "**/*.spec.ts"]
}

but I noticed that Visual Studio Code gets the definition for the Error class from:

C:\Users\kg\AppData\Local\Programs\Microsoft VS Code\resources\app\extensions\node_modules\typescript\lib\lib.es5.d.ts

How do I make TypeScript see that there's a code property in Error without having to define my own type or interface?