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186
VistasHow to send POST request from browser?
I'm trying to make a server in java that can handle requests sent from the browser. My problem is that I can't get the browser to actually send the request, all it sends is an OPTIONS request. Here's the error in the browser:
It isn't an actual website that I'm using, it's just an html page that would be opened by the java application. Here's the html:
<!DOCTYPE html>
<html>
<body>
<button type="button" onclick="sendRequest()">Click Me!</button>
<script>
function sendRequest() {
var xhr = new XMLHttpRequest();
xhr.open("POST", "http://172.26.48.1:9000/test", true);
xhr.setRequestHeader("Content-Type", "application/json");
xhr.send(JSON.stringify({
"time": 16400
}));
}
</script>
</body>
</html>And here's the java server that listens for the requests:
public class ServerTest
{
public static void main(String[] args) throws Exception
{
HttpServer server = HttpServer.create(new InetSocketAddress(9000), 0);
server.createContext("/test", new MyHandler());
server.setExecutor(null);
server.start();
}
static class MyHandler implements HttpHandler
{
public void handle(HttpExchange exchange) throws IOException
{
System.out.println("Handling request: " + exchange.getRequestMethod());
if (exchange.getRequestMethod().equalsIgnoreCase("POST") ||
exchange.getRequestMethod().equalsIgnoreCase("OPTIONS"))
{
try
{
InputStream is = exchange.getRequestBody();
StringBuilder sb = new StringBuilder();
for (int ch; (ch = is.read()) != -1;)
sb.append((char) ch);
System.out.println(sb.toString());
String response = "OK";
exchange.sendResponseHeaders(200, response.length());
OutputStream os = exchange.getResponseBody();
os.write(response.getBytes());
os.close();
exchange.close();
} catch (NumberFormatException e)
{
e.printStackTrace();
}
}
}
}
}
The server works fine, but it only receives the OPTIONS request. How can I make the html page send the actual POST request?
·
Juan Pablo Isaza
1 Respuestas
Responde la pregunta0
function sendRequest() {
var xhttp = new XMLHttpRequest();
xhttp.open("POST", "http://172.26.48.1:9000/test", true);
xhttp.setRequestHeader("Content-Type", "application/json");
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
// Response
var response = this.responseText;
}
};
xhttp..send(JSON.stringify({
"time": 16400
}));
}
·
Juan Pablo Isaza
Denunciar
Responde la pregunta