I have an arrays of object,
var date = [{age:5, name:"al"},
{age:10, name:"ben"},
{age:15, name:"mac"},
{age:15, name:"sarah"},
{age:20, name:"jack"},
{age:24, name:"dan"}
];
and
var age = [15, 23];
For each age, how can I filter the array (named "data") that contain the exact match, and if there is no exact match, it will return the element that in between (closest lower value & closest upper value)?
For example for this case, for each age (15 and 23) it supposed to give me:
[[{age:15, name:"mac"},{age:15, name:"sarah"}],[{age:20, name:"jack"},{age:24, name:"dan"}]].
I try to use this:
function int(){
var data = [{age:5, name:"al"},
{age:10, name:"ben"},
{age:15, name:"mac"},
{age:15, name:"sarah"},
{age:20, name:"jack"},
{age:24, name:"dan"}
];
var age = [15, 23];
var filterData = age.map(n => data.filter(v => n==v.age));
}
But it only resolved the exact match value. However, I cant figured out how to get for in between values (closest lower & closest upper). In this case, for age 23, i supposed to get [{age:20, name:"jack"},{age:24, name:"dan"}].
Any help or tips would be appreciated. I have searched and cannot find a solution.
const data = [
{
age: 5,
name: "al"
},
{
age: 10,
name: "ben"
},
{
age: 15,
name: "mac"
},
{
age: 15,
name: "sarah"
},
{
age: 20,
name: "jack"
},
{
age: 24,
name: "dan"
}
];
const age = [15, 23];
function lowerAndUpperBound(value) {
let lower = { age: -1 };
let upper = { age: 9999 };
for (const obj of data) {
if (obj.age === value && lower.age !== value) {
lower = obj;
}
if (obj.age === value && upper.age !== value) {
upper = obj;
}
if (obj.age > lower.age && obj.age < value && lower.age !== value) {
lower = obj;
}
if (obj.age < upper.age && obj.age > value && upper.age !== value) {
upper = obj;
}
}
return [lower, upper];
}
const result = age.map((i) => lowerAndUpperBound(i));
console.log(result);
Just write an if statement to check if the length of 'filtered' is 0 or not
Also use let instead of Var
function int(d, a){
a = a.sort();
//Basically same thing u wrote
let filtered = d.filter((e)=>age.includes(e.age));
if (filtered.length == 0) {
//Assumes the length of "a" is 2
return d.filter((e)=> e.age >= a[0] && e.age <= a[1])
} else {
//If there is a result, return it
return filtered
}
}
let date1 = [{age:5, name:"al"},
{age:10, name:"ben"},
{age:15, name:"mac"},
{age:15, name:"sarah"},
{age:20, name:"jack"},
{age:24, name:"dan"}
];
let date2 = [{age:5, name:"al"},
{age:10, name:"ben"},
{age:20, name:"jack"},
{age:24, name:"dan"}
];
let age = [15, 23];
console.log(int(date1, age));
// Will result in this, has exact match:
/*
[
{
"age": 15,
"name": "mac"
},
{
"age": 15,
"name": "sarah"
}
]
*/
console.log(int(date2, age));
//Will result in this, has no exact match
/*
[
{
"age": 20,
"name": "jack"
}
]
*/
Try this, this is very easy to understand .
var date = [{age:5, name:"al"},
{age:10, name:"ben"},
{ age:15, name:"mac"},
{age:15, name:"sarah"},
{age:20, name:"jack"},
{age:24, name:"dan"} ];
var age = [15, 23];
const ans = date.filter(val=>age.includes(val.age)) ;
console.log(ans)