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Javascript - Mix two arrays of objects ordering by date and without repetitions

I have two lists:

let originalDocs = [
  {
    id: "sara",
    date: new Date("01/01/2022")
  },
  {
    id: "vic",
    date: new Date("10/26/2020")
  }
];

let newDocs = [
   {
     id: "vic",
     date: new Date("01/02/2022")
   },
   {
     id: "raul",
     date: new Date("05/05/2021")
   }
];

I need to mix both lists, ordering by date (in descending order) and without repetitions.

In order to do that, I have decided to:

Delete the set of elements of the original array that are included in the new array (I mean, deleting the intersection) without modifying the original array.
Mix the resulted array ordering by date.

This is my current code:

function removeIntersection(originalDocs, newDocs) {
  return  originalDocs.filter((originalDoc) => {
    const index = newDocs.findIndex(
      (newDoc) => newDoc.id === originalDoc.id
    );

    return index === -1;
  });
}

function mixInOrder(originalDocs, newDocs) {
   return [...newDocs, ...originalDocs]
    .sort((a, b) => b.date - a.date);
}


//
// MAIN
//

let originalDocs = [
  {
    id: "sara",
    date: new Date("01/01/2022")
  },
  {
    id: "vic",
    date: new Date("10/26/2020")
  }
];

let newDocs = [
  {
    id: "vic",
    date: new Date("01/02/2022")
  },
  {
    id: "raul",
    date: new Date("05/05/2021")
  }
];

const result = mixInOrder(
  removeIntersection(originalDocs, newDocs),
  newDocs
);

console.log(result);

How can I do the same in a more optimal way, I mean, without the need of merging (using the spread syntax) the list before sorting it, or deleting the intersection in O(1).

I mean, is it possible to just insert in order avoiding the copy?

about 4 years ago · Juan Pablo Isaza

2 Respuestas

Responde la pregunta

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You can easily achieve the result using Set and reduce as:

Create a new array by adding the originalDocs first and then newDocs afterwards.
Use reduce to loop over the newly created array and then filter the objects.

You can use Set to check for existence of a key in efficient way

After filtering, you can then sort it accordingly.

let originalDocs = [
  {
    id: 'sara',
    date: new Date('01/01/2022'),
  },
  {
    id: 'vic',
    date: new Date('10/26/2020'),
  },
];

let newDocs = [
  {
    id: 'vic',
    date: new Date('01/02/2022'),
  },
  {
    id: 'raul',
    date: new Date('05/05/2021'),
  },
];

const set = new Set();
const result = [...originalDocs, ...newDocs].reduce((acc, curr) => {
    if (!set.has(curr.id)) {
      acc.push(curr);
      set.add(curr.id);
    }
    return acc;
  }, [])
  .sort((a, b) => b.date - a.date);
console.log(result);

about 4 years ago · Juan Pablo Isaza Denunciar

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Responde la pregunta

Encuentra empleos remotos

Accepted Answer · 2022-07-05T14:33:05.517Z

Here's how to do this using a JS Map, where you use the id as identifier:

let originalDocs = [
  {
    id: "sara",
    date: new Date("01/01/2022")
  },
  {
    id: "vic",
    date: new Date("10/26/2020")
  }
];

let newDocs = [
  {
    id: "vic",
    date: new Date("01/02/2022")
  },
  {
    id: "raul",
    date: new Date("05/05/2021")
  }
];
const map = new Map(originalDocs.map(el => [el.id, el]));
newDocs.forEach(el => map.set(el.id, el));
const sorted = [...map.values()].sort((a, b) => a.date - b.date);
console.log(sorted)

This overrides any originalDocs entry with a newDocs entry if they have the same id.

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141

Javascript - Mix two arrays of objects ordering by date and without repetitions

2 Respuestas

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Encuentra empleos remotos

Andres GPT