so I have the following tree structure:
const tree = {
id: "1",
tag: "pending",
subtasks: [
{ id: "2", tag: "pending", subtasks: [] },
{
id: "3",
tag: "in progress",
subtasks: [
{
id: "4",
tag: "pending",
subtasks: [
{
id: "6",
tag: "in progress",
subtasks: [
{
id: "10",
tag: "pending",
subtasks: [{ id: "11", tag: "complete", subtasks: [] }]
}
]
},
{ id: "7", tag: "complete", subtasks: [] }
]
},
{ id: "5", tag: "pending", subtasks: [] }
]
},
{ id: "4", tag: "complete", subtasks: [] }
]
};
and I want to remove any node that has the "in progress" tag. But, I also want to keep the children of the removed node if their tags are not "in progress" out. They will be kept by moving them to the same depth and index levels of their parent.
so, the result will look something like this:
const filteredTree = {
id: "1",
tag: "pending",
subtasks: [
{ id: "2", tag: "pending", subtasks: [] },
{
id: "4",
tag: "pending",
subtasks: [
{
id: "10",
tag: "pending",
subtasks: [{ id: "11", tag: "complete", subtasks: [] }]
},
{ id: "7", tag: "complete", subtasks: [] }
]
},
{ id: "5", tag: "pending", subtasks: [] },
{ id: "4", tag: "complete", subtasks: [] }
]
};
how can I achieve that?
You could remove by checking tag and take either the filtered subtasks or a new object with filtered subtasks.
const
remove = tag => ({ subtasks, ...node }) => {
subtasks = subtasks.flatMap(remove(tag));
return node.tag === tag
? subtasks
: [{ ...node, subtasks }]
},
tree = { id: "1", tag: "pending", subtasks: [ { id: "2", tag: "pending", subtasks: [] }, { id: "3", tag: "in progress", subtasks: [{ id: "4", tag: "pending", subtasks: [{ id: "6", tag: "in progress", subtasks: [{ id: "10", tag: "pending", subtasks: [{ id: "11", tag: "complete", subtasks: [] }] }] }, { id: "7", tag: "complete", subtasks: [] }] }, { id: "5", tag: "pending", subtasks: [] }] }, { id: "4", tag: "complete", subtasks: [] }] },
result = remove('in progress')(tree);
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }