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VistasProblem in rendering ejs template with Express
I am using Node.js together with Express and EJS.
Below is my code:
var express = require('express');
var path = require('path');
var bodyParser = require('body-parser');
var app = express();
var urlencodedParser = bodyParser.urlencoded({ extended: false });
var publicPath = path.resolve(__dirname, 'public');
app.use(express.static(publicPath));
//app.set('views', __dirname + '/views');
app.set('view engine', 'ejs');
app.get('/form_get.html', (req, res) => {
res.sendFile(__dirname + "/" + "form_get.html")
})
app.get('/process_get', (req, res) => {
console.log(req.query.first_name);
res.render(path.join(__dirname+'/views/thankyou.ejs'), { name: req.query.first_name});
})
var server = app.listen(3000, () => {
var host = server.address().address;
var port = server.address().port;
console.log(`Example app listening at ${host}:${port}`);
})
My folder structure is below:
- mysql (folder)
- node_modules (folder)
- app4.js (file)
- package.json (file)
- public (folder, it contains form_get.html)
- views (folder, it contains thankyou.ejs)
The problem is the failing to look up thankyou.ejs into the views folder.
I get the following error message:
Error: Failed to lookup view "thankyou.ejs" in views directory ".../mysql/views"
What can be the problem?
·
Juan Pablo Isaza
1 Respuestas
Responde la pregunta0
When You use app.set('view engine', 'ejs'); It is important to note that res.render() will look in a views folder for the view.
In this case
I mirrored Your project and it works fine with couple tiny changes...
Project Folder and file structure.
app.js
var express = require("express");
var path = require("path");
var bodyParser = require("body-parser");
var app = express();
var urlencodedParser = bodyParser.urlencoded({ extended: false });
var publicPath = path.resolve(__dirname, "public");
app.use(express.static(publicPath));
app.set("view engine", "ejs");
app.get("/form_get", (req, res) => {
res.sendFile(__dirname + "/" + "form_get.html");
});
app.get("/process_get", (req, res) => {
res.render("thankyou");
});
var server = app.listen(3000, () => {
var host = server.address().address;
var port = server.address().port;
console.log(`Example app listening at ${host}:http://localhost:${port}`);
});
Output:
http://localhost:3000/process_get (thankyou.ejs) file.
Output:
http://localhost:3000/form_get (form_get.html) file
·
Juan Pablo Isaza
Denunciar
Responde la pregunta