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VistasHow to set bounds for spinal line with axisartist?
How can I set the bounds of axisartist.axis[].line?
With the normal API, its possible to set bounds of the axis spine with:
ax.spines['right'].set_bounds(low=0.01,high=0.1)
But axisartist does not have a spines object. Instead, spinal lines are implemented with ax.axis['left'].line, which does not have a get_bounds and set_bounds method.
Example:
import numpy as np
import matplotlib.pyplot as plt
import mpl_toolkits.axisartist as axisartist
import seaborn as sns
use_artist = True
x = np.random.random(10)
y = np.random.random(10)
x.sort()
y.sort()
if use_artist:
fig = plt.figure()
ax = fig.add_subplot(axes_class=axisartist.Axes)
else:
fig, ax = plt.subplots()
ax.scatter(x, y, marker="o")
if use_artist:
ax.axis['right'].set_visible(False)
ax.axis['top'].set_visible(False)
# HOW TO SET BOUNDS OF ax.axis['left'].line here?
else:
sns.despine()
ax.spines['left'].set_bounds(ax.get_yticks()[1], ax.get_yticks()[-2])
ax.spines['bottom'].set_bounds(ax.get_xticks()[1], ax.get_xticks()[-2])
plt.tight_layout()
plt.draw()
plt.show()
Here are examples without and with axisartist:
·
Santiago Trujillo
1 Respuestas
Responde la pregunta0
Use axes.set_xbounds() or axes.set_xlim() (docs found here and here respectively). Both methods appear identical in function, but set_xlim has more functionality, should you require it. So your new modified code using only axisartist is:
import numpy as np
import matplotlib.pyplot as plt
import mpl_toolkits.axisartist as axisartist
# Data
x = np.random.random(10)
y = np.random.random(10)
x.sort()
y.sort()
# Creating figure, plot
fig = plt.figure()
ax = fig.add_subplot(axes_class=axisartist.Axes)
ax.scatter(x, y, marker="o")
# Formatting axes
ax.axis['right'].set_visible(False)
ax.axis['top'].set_visible(False)
ax.axis['left'].major_ticklabels.set_pad(10)
ax.axis['bottom'].major_ticklabels.set_pad(10)
# Setting axis limits
ax.set_xlim(left=0.2, right = 0.5)
ax.set_ylim(bottom=0, top = 0.7)
plt.tight_layout()
plt.draw()
plt.show()
·
Santiago Trujillo
Denunciar
Responde la pregunta