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Python - Can Multiple if-condition and append be simplified

If it is possible to simplify the following code.

c0, c1, c2, c3, c4, c5, c6, c7, c8, c9 = ([] for _ in range(10))
  
  for i in dataset:
    if i[1] == 0:
      c0.append(i)
    elif i[1] == 1:
      c1.append(i)
    elif i[1] == 2:
      c2.append(i)
    elif i[1] == 3:
      c3.append(i)
    elif i[1] == 4:
      c4.append(i)
    elif i[1] == 5:
      c5.append(i)
    elif i[1] == 6:
      c6.append(i)
    elif i[1] == 7:
      c7.append(i)
    elif i[1] == 8:
      c8.append(i)
    else:
      c9.append(i)

Trying to divide the whole dataset into class-wise multiple datasets. Code below is just for example which has only 10 classes, but the dataset I'm working on has massive numbers of classes, so need to simplify as possible.

over 4 years ago · Santiago Trujillo
3 Respuestas
Responde la pregunta

0

Better with a list:

lsts = [c0, c1, c2, c3, c4, c5, c6, c7, c8]
for i in dataset:
    if i[1] < len(lsts):
        lsts[i[1]].append(i)
    else:
        c9.append(i)

And the lists will contain what you want :)

over 4 years ago · Santiago Trujillo Denunciar

0

How about like this?

Use dictionary instead of nested lists like c0, c1, c2

c = {x:[] for x in range(10)}
  
for i in dataset:
    c[i[1]].append(i)

If you want to append other items in the dataset to the c9 as like you mentioned in your question, then

for i in dataset:
    if 0 <= i[1] <= 8:
        c[i[1]].append(i)
    else:
        c[9].append(i)
over 4 years ago · Santiago Trujillo Denunciar

0

you can use it.

# if you need cX as var
c0, c1, c2, c3, c4, c5, c6, c7, c8, c9 = ([] for _ in range(10))
database = {0: c0,
            1: c1,
            2: c2,
            ...,
            9: c9}

# else
database = {i: [] for i in range(10)}

for i in dataset:
    if i[1] in dataset:
        database[i].append(i)
    else:
        database[9].append(i)
over 4 years ago · Santiago Trujillo Denunciar
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