I am kind of new to async/await in javascript by have used suspend functionalities in Kotlin before. Is there any way to await and catch error if any in js. (without writing try catch). If not what is the right way to do this.
For example consider this snippet, async function a:
let a = async () => {
// does io and returns result
}
Now, consider a function b which calls a. Can I write it in this clean way:
let a = async () => {
const result_of_a = (await a()).catch(() => { // handle error })
// work with `result_of_a`
}
Rather than
let a = async () => {
var result_of_a = null
try {
result_of_a = await a()
} catch (e) {
}
// work with `result_of_a`
}
Is there any other pretty way of writing the above sub-routine
I don't believe you can. If you think .catch is cleaner perhaps you should just use promise syntax. Personally I use both, depending on the context. But I favor async due to promise hell
let asyncFn = async () => {
const result = a().then(...).catch(...)
}
Can you try this way :
let b = async () => {
const result_of_a = await a().then(()=>{
// handle success response here and return value
},
()=>{
// handle success response here and return value you want
}
)
// You will get value return in `result_of_a`
}
Use catch on a promise that is returned from your function. You mixed up two different approaches.