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VistasSorting data and its children using Javascript
I have data. There are other data of the same type that have children in this data. I want to sort them all according to their 'id' fields, but I couldn't set up the algorithm scheme for it.
What I've tried:
const sortedData: [] = [];
function sortAscending(datas: Group[]) {
sortedData.push(datas.sort((group1, group2) => group1.id - group2.id ));
return sortedData;
}
With this code, I can only sort without children.
I tried to model the picture I wanted to describe:
Note: The returned data will be mapped and used later.
Sample array:
0:
children: [{…}]
id: 1
name: "name1"
[[Prototype]]: Object
1:
children: []
id: 7
name: "name2"
[[Prototype]]: Object
The 'children' field also has 'children', 'id' and 'name' fields just like themselves. What I want is to sort both the data itself and the data in the children field in it according to their 'id' fields.
1 Respuestas
Responde la pregunta0
first you need to know that array sort method sorts the array in-place it means it changes the array you pass to it. so
const rawData= [...] // your raw, un-sorted data
function sortAscending(data){...} // your function that does sorting
sortAscending(rawData) // after this, your array gets sorted 'in-place'
second, if your data has children and those children have their own children and you want them all be sorted ascending you need to write some recursive algorithm.
for example:
function sortAscending(data){
data.sort((group1, group2) => group1.id - group2.id));
for(group of data){
if (group.children.length) sortAscending(group.children);
}
}