Suppose I have these documents:
[
{
_id: 132143124,
orders: [true, false, false],
},
{
_id: 3123,
orders: [true, true, true],
},
];
How do I get only the documents that dont have 'false' in their orders array. I need an aggregate stage solution. ( MongoDB aggregate solution )
You can use $not or $ne ( as Mongo's query language flattens arrays ) for this, like so:
db.collection.find({
orders: {$ne: false}
})
same syntax will work in the aggregation pipeline: Mongo Playground Aggregation
You could use filter function for arrays:
const results = [
{
_id: 1,
orders: [true, false, false],
}, {
_id: 2,
orders: [true, true, true],
}
]
const filtered_results = results.map(({orders, ...data}) => {
return {
orders: orders.filter((order)=>order === true),
...data
}
})
console.log(filtered_results)