I try to create a regex with 2 condition:
I need to add spaces
So like: iph12 return iph12, but iphone12 return iphone 12
I wrote regex
.replace(/\d+/gi, ' $& ').trim()
and this function return in anyway string like iphone 12. I tried to use function
.replace(/(?=[A-Z]+\d|\d+[A-Z])[A-Z\d]{,4}/i, ' $& ').trim()
but without second argument in {,4} it's not working. So is this possible?
You can use
text.replace(/\b([a-zA-Z]{4,})(\d+)\b/g, '$1 $2')
See the regex demo. Details:
\b - word boundary([a-zA-Z]{4,}) - Group 1: four or more ASCII letters(\d+) - Group 2: one or more digits\b - word boundarySee the JavaScript demo:
const texts = ['iphone12', 'iph12'];
const regex = /\b([a-zA-Z]{4,})(\d+)\b/g;
for (const text of texts) {
console.log(text, '=>', text.replace(regex, '$1 $2'));
}Output:
iphone12 => iphone 12
iph12 => iph12