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Struggling with Number.isInteger()

I have an assignment to make a converter from decimal to binary numbers and vice versa. I have done everything I need, but I have no idea how to protect the site from the user entering a number with the part after the decimal point.

So I fooled around the internet and found Number.isInteger(), yet I have no idea how this works. Tried writing some test stuff (as you can observe beneath this wall of text) but nothing seemed to work. Can anyone offer any help as to how exactly Number.isInteger() works?

pepege() {
  var a = +document.getElementById("x").value;
  var b = Number.isInteger(a);
  document.getElementById("out").innerHTML = b;
}
<input type="text" id="x">
<br>
<input type="button" value="xddddd" onclick="pepege();">
<br>
<a id="out"></a>

Thanks for any and all advice on how to move forward with this.

about 4 years ago · Juan Pablo Isaza
2 Respuestas
Responde la pregunta

0

You can add event listener and force user to enter just number. As i understand you are having problem with user inputs

const pepege = () => {
  var a = +document.getElementById("x").value;
  var b = Number.isInteger(a);
  document.getElementById("out").innerHTML = b;
}

 
document.getElementById("x").addEventListener("input", event => {
  document.getElementById("x").value = document.getElementById("x").value.replace(/[^0-9.]/g, '').replace(/(\..*?)\..*/g, '$1')
});
<input type="text" id="x">
<br>
<input type="button" value="xddddd" onclick="pepege();">
<br>
<a id="out"></a>

about 4 years ago · Juan Pablo Isaza Denunciar

0

Wrap your var a in parseFloat(). Input type text always returns a string. With parseFloat(), you'll get NaN for non-numeric characters, a float for a float, and an integer for an integer.

function pepege() {
  var a = parseFloat(document.getElementById("x").value);
  var b = Number.isInteger(a);
  document.getElementById("out").innerHTML = b;
}
<input type="text" id="x">
<br>
<input type="button" value="xddddd" onclick="pepege();">
<br>
<a id="out"></a>

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
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