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Extract text until second to last occurrence from string

How do I extract the text from the beginning until (not including) the second to last occurrence of a charachter (":" in this case) from a string? Preferably without using regex.

Examples:

"urn:riv:intygsbestallning:certificate:order:RequestPerformerForAssessmentResponder:1" should become "RequestPerformerForAssessmentResponder:1"

"urn:riv:itinfra:tp:PingResponder:1" should become "PingResponder:1"

almost 3 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

with split function you can parse your string returning an array of the tokens separated from the string in the parameter of split and later you can concatenate last two items in the array

let x = "urn:riv:intygsbestallning:certificate:order:RequestPerformerForAssessmentResponder:1";

let result = x.split(":");
let yourTextResult = `${result[result.length-2]}:${result[result.length-1]}`;
console.log(yourTextResult );

almost 3 years ago · Juan Pablo Isaza Denunciar

0

const data1 = "urn:riv:intygsbestallning:certificate:order:RequestPerformerForAssessmentResponder:1";
const data2 = "urn:riv:itinfra:tp:PingResponder:1"

const arr = data1.split(':');
console.log(arr.splice(arr.length-2,arr.length).join(':'))

almost 3 years ago · Juan Pablo Isaza Denunciar

0

str = 'urn:riv:intygsbestallning:certificate:order:RequestPerformerForAssessmentResponder:1'

split_array = str.split(':')
ans = split_array.splice(-2).join(':')

console.log('ans', ans)

cut_off_part = split_array.join(':') + ':'
console.log('cut_off part', cut_off_part)
    

Another way of doing the same:

str = 'urn:riv:intygsbestallning:certificate:order:RequestPerformerForAssessmentResponder:1'

ans = str.split(':').splice(-2).join(':')
console.log("answer", ans)

cutoff_part = str.substr(0, str.length - ans.length)
console.log("cut_off_part", cutoff_part)

almost 3 years ago · Juan Pablo Isaza Denunciar
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