how I could validate that an object has all the properties of an interface.
For example:
interface Vehicle {
name: string
model: string
}
interface User {
Name: string
age: númber
}
interface Customer extends User {
vehicles: Vehicle[]
}
How could I check that an object has all the properties of Customer interface????
If by "validate that an object has all the properties of an interface" you mean static type checking, well that's Typescripts job and it will do that at compile time if you use try to assign the object to a variable of that interface type. e.g.:
const obj = {name: 'Edwin', age: 35}
let c: Customer = obj // this will fail at compile time
Typescript at runtime is just Javascript, and Javascript does not have a first class support for interfaces. In fact, Vehicle, User and Customer will not even exist at runtime because of type erasure. For more info see these this and this in the Typescript Handbook and docs. So you cannot reference these types in any runtime logic. The Javascript instanceof operator only works for Javascript prototype inheritance, and has very specific meaning:
The instanceof operator tests to see if the prototype property of a constructor appears anywhere in the prototype chain of an object. The return value is a boolean value.
The Javascript typeof operator only works for primitive types, like string.
If you need to do runtime "type checking", you will have to do that manually, checking for the existence of each field, and its type recursively.
Typescript has some syntactic sugar to make such manual checks look natural in your Typescript source code. Read about Narrowing and Type Guards.
There my even be a library that implements that for you. In fact I do remember coming across a library that generates runtime type checking based on Typescript definition... Let me find it really quick...
Some examples (there are more):