Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

191
Vistas
How to get the difference between latest and previous data in an array within one hour using javasscript?

I have this array of objects:

0: {time: '2021-12-02T23:53:54.062Z', value: 558316}
1: {time: '2021-12-03T00:53:53.959Z', value: 558452}
2: {time: '2021-12-03T01:53:53.934Z', value: 558588}
3: {time: '2021-12-05T23:53:48.617Z', value: 568039}
4: {time: '2021-12-06T00:53:48.609Z', value: 568174}
5: {time: '2021-12-06T01:53:48.545Z', value: 568309}
6: {time: '2021-12-06T02:53:48.480Z', value: 568444}
7: {time: '2021-12-06T03:53:48.393Z', value: 568579}

Question is how to get the difference of value per hour, for example value from 1: 558452 subtract to value from 0: 558316 equals 136. But do not subtract if current and previous value is not within one hour for example value from 3: 568039 subtract to value from 2: 558588, value from 3 is more than an hour from value from 2. So this two should not be subtracted, because it will get high value(9,451) in graph.

expected result:

{time: '2021-12-03T00:53:53.959Z', value: 136}
{time: '2021-12-03T01:53:53.934Z', value: 136}
{time: '2021-12-06T00:53:48.609Z', value: 135}
{time: '2021-12-06T01:53:48.545Z', value: 135}
{time: '2021-12-06T02:53:48.480Z', value: 135}
{time: '2021-12-06T03:53:48.393Z', value: 135}
about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

You could use map to calculate the difference, and then filter based on this..

eg.

var data = [
 {time: '2021-12-02T23:53:54.062Z', value: 558316},
 {time: '2021-12-03T00:53:53.959Z', value: 558452},
 {time: '2021-12-03T01:53:53.934Z', value: 558588},
 {time: '2021-12-05T23:53:48.617Z', value: 568039},
 {time: '2021-12-06T00:53:48.609Z', value: 568174},
 {time: '2021-12-06T01:53:48.545Z', value: 568309},
 {time: '2021-12-06T02:53:48.480Z', value: 568444},
 {time: '2021-12-06T03:53:48.393Z', value: 568579},
].map(d => (d.time = new Date(d.time), d));

const oneHour = 1000 * 60 * 60;

const temp = data.map((m, ix, a) => {
  if (ix > 0) {
    m.diff = a[ix].time - a[ix -1].time;
    m.value2 = a[ix].value - a[ix -1].value;
  } else {
    //make first one filter out as
    //there is no previous
    m.diff = oneHour + 1;
  }
  return m;
})
.filter(m => m.diff < oneHour)
.map(m => ({
  time: m.time,
  value: m.value2
}));

console.log(temp);

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda