let linkMatrix = [
[0,0,1,0],
[1,0,0,1],
[1,1,0,1],
[0,1,0,0]
];
let newMatrix = [];
function linkToPage(){
for(let j = 0; j < linkMatrix.length; j--){
newMatrix = linkMatrix.splice(linkMatrix[j], 1);
console.log(linkMatrix + " Here is linkMatrix");
for(let i = 0; i < newMatrix.length; i++){
newMatrix.splice(newMatrix[i]);
console.log(newMatrix + " Here is newMatrix");
}
}
**What i'm trying to do is loop throug the first array but remove the fist array, because i don't need to loop throug that, then loop throug the rest of the arrays, but the only value i need is the value in the removed array's index, so to better understand: if we had an array that wore somthing like this arr = [[0,1],[1,0],[1,1]] then remove [0,1] and because it is arr[0], i would like to loop throug the 0 index of the other arrays so i would get 1 and 1, then go back to the original array remove arr[1] and loop throug arr[0],arr[2] to the 1 index of the arrays so i would get [1,1] **
**Yeah, so the wanted result from my link matrix would be:
[0,0,1,0] = 2
[1,0,0,1] = 2
[1,1,0,1] = 1
[0,1,0,0] = 2
because there is 2 other arrys pointing to the first array, the same for the second and fourth, but there is only one array pointing to the third array
**
You could add the values of the columns.
const
getColSum = matrix => matrix.reduce((r, a) => a.map((v, i) => (r[i] || 0) + v), []);
console.log(...getColSum([[0, 0, 1, 0], [1, 0, 0, 1], [1, 1, 0, 1], [0, 1, 0, 0]]));
console.log(...getColSum([[0, 0, 0], [1, 0, 0], [1, 1, 0]]));A version without (nearly) array methods.
function getColSum (matrix) {
const result = Array(matrix[0].length).fill(0);
for (const row of matrix) {
for (let i = 0; i < row.length; i++) result[i] += row[i];
}
return result;
}
console.log(...getColSum([[0, 0, 1, 0], [1, 0, 0, 1], [1, 1, 0, 1], [0, 1, 0, 0]]));
console.log(...getColSum([[0, 0, 0], [1, 0, 0], [1, 1, 0]]));