i have a promise chain
If i receive error in getServiceCost I want to repeat the chain again (retry) for 2 times how can i achieve this when using Promise chain , meaning again execute getUser, getServiceCost
getUser(100)
.then(getServices)
.then(getServiceCost)
.then(console.log);
function getUser(userId) {
return new Promise((resolve, reject) => {
console.log('Get the user from the database.');
setTimeout(() => {
resolve({
userId: userId,
username: 'admin'
});
}, 1000);
})
}
function getServices(user) {
return new Promise((resolve, reject) => {
console.log(`Get the services of ${user.username} from the API.`);
setTimeout(() => {
resolve(['Email', 'VPN', 'CDN']);
}, 3 * 1000);
});
}
function getServiceCost(services) {
return new Promise((resolve, reject) => {
console.log(`Calculate the service cost of ${services}.`);
setTimeout(() => {
resolve(services.length * 100);
}, 2 * 1000);
});
}
If i receive error in getServiceCost I want to repeat the chain again (retry) for 2 times how can i achieve this when using Promise chain , meaning again execute getUser, getServiceCost
I'd use an async function (all modern environments support them, and you can transpile for obsolete environments), which lets you use a simple loop. Perhaps as a utility function you can reuse:
async function callWithRetry(fn, retries = 3) {
while (retries-- > 0) {
try {
return await fn();
} catch (error) {
if (retries === 0) {
throw error;
}
}
}
return new Error(`Out of retries`); // Probably using an `Error` subclass
}
Using it:
callWithRetry(() => getUser(100).then(getServices).then(getServiceCost))
.then(console.log)
.catch(error => { /*...handle/report error...*/ });
Or
callWithRetry(async () => {
const user = await getUser(100);
const services = await getServices(user);
return await getServiceCost(services);
})
.then(console.log)
.catch(error => { /*...handle/report error...*/ });