I was experimenting whether I can use "logical or" inside case clause for a switch statement. I tried this way for the first case and the system skipped it all together when I gave input as "A" or "a" in both the cases.
# include <iostream>
using namespace std;
int main () {
/* prg. checks if the input is an vowel */
char ch;
cout << "please input a word to check if it is vowel or not" << endl;
cin >> ch;
switch (ch) {
case ('A'|| 'a') :
cout << "it is vowel" << endl;
break;
case 'E':
cout << "it is vowel" << endl;
break;
case 'I':
cout << "it is vowel" << endl;
break;
case 'O':
cout << "it is vowel" << endl;
break;
case 'U':
cout << "it is vowel" << endl;
break;
default:
cout << "it is not a vowel" << endl;
break;
}
is there a proper way to use or inside the case clause ?
Thank you for the help.
The case ('A'|| 'a') should be written as:
switch (ch) {
case 'A':
case 'a':
cout << "it is vowel" << endl;
break;
// ...
If it matches on 'A' it will fall through to the next case (unless there's a break in between).
In this case, you may want to combine all vowles:
switch (ch) {
case 'A':
case 'a':
case 'E':
case 'e':
//... all of them ...
std::cout << "it is vowel\n";
break;
// ...
Note that some compilers will issue a warning for fall through cases with statements in them (which is not the case above). Since C++17, if you use fall through cases, you can use the fallthrough attribute to silence such warnings where you actually want a fall through.