I couldn't find any documentation or questions about whether it's possible to write the case statements in a switch statement on one line nor what the best practice and way to write them on one line in JavaScript is.
The most related questions were: CodeGrepper Question and Switch statement for multiple cases in JavaScript
I currently have a function with a switch statement that returns a product's name:
function returnProduct(product) {
switch (product) {
case 'aa': case 'AApple':
return 'AApple';
case 'bb': case 'BananaBall':
return 'BananaBall';
case 'ee': case 'ElephantElf':
return 'ElephantElf';
default:
return 'Sorry we don\'t have that yet';
}
}
console.log(returnProduct('aa'));
console.log(returnProduct('error'));
console.log(returnProduct('ee'));
console.log(returnProduct('BananaBall'));Solution 1
Thanks to @Ryan Wheale, @Bergi and @T.J. Crowder who helped me realize that since Javascript doesn't require line breaks it could all be written on one single line separated by; and I don't need to put any {} around the return statements. While the following code snippet does answer my question, it's also important to mention that a one liner like this is not at all readable and should be avoided.
function returnProduct(product) { switch (product) { case 'aa': case 'AApple': return 'AApple'; case 'bb': case 'BananaBall': return 'BananaBall'; case 'ee': case 'ElephantElf': return 'ElephantElf'; default: return 'Sorry we don\'t have that yet'; } } console.log(returnProduct('aa')); console.log(returnProduct('error')); console.log(returnProduct('ee')); console.log(returnProduct('BananaBall'));switch statement.function returnProduct(product) {
switch (product) {
case 'aa': case 'AApple': return 'AApple';
case 'bb': case 'BananaBall': return 'BananaBall';
case 'ee': case 'ElephantElf': return 'ElephantElf';
default: return 'Sorry we don\'t have that yet';
}
}
console.log(returnProduct('aa'));
console.log(returnProduct('error'));
console.log(returnProduct('ee'));
console.log(returnProduct('BananaBall'));This was my first proposed solution which solves my problem but I hadn't tested it enough and had some errors which the community helped me fix.
I hope that others asking the same question will be able to find this as a useful answer to the same question I had.
Seems you have missed the break statement. Or Try using dictionary
var x ='aa':'AApple','AApple':'AApple','bb':'BananaBall',
'BananaBall':'BananaBall'};
var key='aa';
var z;
if(x[key] !== undefined)
return x[key];