Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

300
Vistas
Variable 'value' is used before being assigned

My code:

function test() {
  let value: number;

  for (let i = 0; i < 10; i++) {
    value = i;
    console.log(value);
  }

  return value;
}

test();

And got this:

Variable 'value' is used before being assigned

I found this very odd, as I had seen other similar problems that either used a callback or a Promise or some other asynchronous method, while I used just a synchronous for loop.

---------------------------------- Some update ------------------------

function test() {
  let value: number;

  for (let i = 0; i < 100; i++) {
    // a() is very expensive and with some effects
    const result = a(i)

    if(i===99) {
      value = result
    }

  }

  return value;
}

about 4 years ago · Juan Pablo Isaza
2 Respuestas
Responde la pregunta

0

Use the non-null assertion operator to ensure that "its operand is non-null and non-undefined in contexts where the type checker is unable to conclude that fact."

function test() {
  let value!: number;

  for (let i = 0; i < 10; i++) {
    value = i;
    console.log(value);
  }

  return value;
}

test();

Result

about 4 years ago · Juan Pablo Isaza Denunciar

0

TypeScript can't infer that anything in the loop body runs - it doesn't check that i starts at 0, and the condition is i < 10, and that the body will run at least once as a result. This behavior is very similar to the following:

function test() {
  let value: number;
  if (Math.random() < 0.5) {
    value = 5;
  }
  return value;
}

which produces the same error.

For TS to know that the value really definitely is defined at the end, you need to make it completely unambiguous. Usually, the best way this is achieved is by defining and assigning to the variable once, with const, through array methods and helper functions - TS works best when reassignment is minimized.

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda