Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

108
Vistas
If condition in a for loop to ensure a string is found in an array

Using an array of 3 words which is randomly generated from another function, I'm trying to get a function to check whether a certain i word in a loop, which is given from the src of an image file, is found in the array generated from that other function, and in case it isn't - that other function would run again until the word would be included in the array.

var gFlavors = ['vanilla', 'chocolate', 'strawberry', 'lemon', 'peanutbutter']

function getFlavor(flavor) {
    var options = [];

    for (var i = 1; i <= gFlavors.length; i++) {
    // I have a folder of images, with the images named "1-vanilla.gif", "2-chocolate.gif" and so on. Using the loop, I am getting those images and setting a class and data for each
    flavor = new Image(150, 150);
    flavor.src = 'img/' + i + '-' + gFlavors[i - 1] + '.gif';
    flavor.setAttribute('class', 'flavor');
    flavor.setAttribute('data-flavor', gFlavors[i - 1]);
    var elFlavorsDiv.appendChild(flavor);

    // Slicing solely the flavor word found in each image filename
    var flavorImgSrc = flavor.attributes.src.nodeValue;
    var flavorImgSrcDash = flavorImgSrc.indexOf('-');
    var flavorStr = flavorImgSrc.slice(flavorImgSrcDash + 1, flavorImgSrc.length - 4);
    options = generateOptions();

    // The problematic line which doesn't do what I want it to: To check whether an i flavor is included in the generated random array (and if it isn't - re-generate the random array until the flavor is included) - For example: The generated random array is ['strawberry', 'peanutbutter', 'chocolate'] - if i is currently one of the 3 flavors found in the array, keep the array as it is, on the other hand if i is for example 'lemon' - re-run generateOptions() until the current i is found there - so I only get an array matching the current i
    if (!options[i].includes(flavorStr)) options = generateOptions();
}


// A function returning an array of 3 random flavors
function generateOptions() {
    var randomizedOptions = gFlavors;
    for (var i = 0; i < 3; i++) {
        shuffle(randomizedOptions);
        randomizedOptions.splice(0, randomizedOptions.length-3)
    }
    return randomizedOptions;
}

// A shuffle function for arrays
function shuffle(array) {
    array.sort(() => (Math.random() - 0.5));
}

Example of expected result: The generated random array is ['strawberry', 'peanutbutter', 'chocolate'] - If i is currently one of the 3 flavors found in the array, keep the array as it is, on the other hand if i is for example 'lemon' - re-run generateOptions() until the current i is found there - so I only get an array matching the current i.

As of now, I am receiving a TypeError: Cannot read properties of undefined (reading 'includes') at getFlavor

about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

Your generateOptions function returns void.

So therefore options is undefined, meaning options[i] would throw.

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda