I have following enhanced switch case
@Override
public MultivaluedMap<String, String> update(MultivaluedMap<String, String> incomingHeaders,
MultivaluedMap<String, String> clientOutgoingHeaders) {
switch (authMethod) {
case BASIC -> clientOutgoingHeaders.add("Authorization", basicAuth("admin", "admin"));
case BEARER -> clientOutgoingHeaders.add("Authorization", "Bearer" + " " + getAccessTokenFromKeycloak());
case SKIP -> System.out.println(); // How can I remove this?
}
return clientOutgoingHeaders;
}
where as authMethod is a
enum AuthMethod{
BASIC,
BEARER,
SKIP
}
If authMethodis SKIP I simply want the code to do nothing. I don't want to remove the case.
I am aware, that I could work around this problem in other different ways, but I am curious if this works with an enhanced switch.
Also I am aware, that I could just remove the SKIP case. That is simply not what I want, because I want to make clear, that SKIP does nothing in that case.
This is what I have tried
case SKIP -> {};
case SKIP -> ();
How can I do nothing in a case of an enhanced switch statement?
This is so close!
case SKIP -> {};
You just had one extra semicolon! Remove it and it compiles!
case SKIP -> {}
See the syntax for a SwitchRule in the Java Language Specification:
SwitchStatement:
switch ( Expression ) SwitchBlock
SwitchBlock:
{ SwitchRule {SwitchRule} }
{ {SwitchBlockStatementGroup} {SwitchLabel :} }
SwitchRule:
SwitchLabel -> Expression ;
SwitchLabel -> Block
SwitchLabel -> ThrowStatement
Notice how, if it is an expression, like your add calls, you need a semicolon after it. If you use a block, like {}, you should not add a semicolon.