Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

204
Vistas
Changing background image setinterval only calling once

This is in REACT.JS. I have combed through the different posts on here trying to find a solution, however I have not been able to get this to run more than once. Any ideas would be greatly appreciated! I have the component code below

import React, { Component } from 'react'
import './Login.css'
import LoginHousing from './LoginHousing'
import bg1 from '../../images/backgrounds/lawn-maintenance.jpg'
import bg2 from '../../images/backgrounds/body-shop.jpg'
import bg3 from '../../images/backgrounds/mechanic.jpg'
import bg4 from '../../images/backgrounds/painting.jpg'
import bg5 from '../../images/backgrounds/hair-stylist.jpg'

export default class Login extends Component {
constructor(){
    super()
    this.state = {loginBg: bg1}
}

// Background slideshow effect on mount, changing every 2 seconds
changingBackground() {
    let i = 0
    const images = [bg1, bg2, bg3, bg4, bg5]

    if (i < images.length - 1) {
        i++;
    } else {
        i = 0;
    }

    this.setState({loginBg: images[i]})
}


componentDidMount() {
    this.timer = setInterval(
        () => this.changingBackground(),
        2000
    );
}

componentWillUnmount(){
    clearInterval(this.timer)
}

render() {
    return (
        <div className='login vw-100 vh-100' style={{backgroundImage: `url(${this.state.loginBg})`}}>
            <LoginHousing />
        </div>
    )
}
}
about 4 years ago · Juan Pablo Isaza
2 Respuestas
Responde la pregunta

0

let i = 0

This variable is local to the function, so each time that function is executed in the interval, you basically start from the beginning.


You could change code to this:

changingBackground() {       
    this.setState((ps) => {
      return {
        index: (ps.index + 1) % this.images.length, // store images in instance field
      };
    });
  }

And then render:

this.images[this.state.index]

PS and constructor:

constructor() {
    super();
    this.state = { index: 0 };
}
about 4 years ago · Juan Pablo Isaza Denunciar

0

I will give you a little explanation before the solution for this, because when you are calling the this.changingBackground() it will always get to zero again, as you see in the first declaration of the let i = 0 so each time that function runs it will be zero, I think the best solution for this is making the counter for the background-images a state variable:

import React, { Component } from 'react';

export default class Login extends Component {
  constructor(){
      super();
      this.state = {loginBg: bg1, indexImage: 0}
  }

  changingBackground() {
      const images = [bg1, bg2, bg3, bg4, bg5]

      if (indexImage < images.length - 1) {
          this.setState({indexImage: this.state.indexImage + 1});
      } else {
          this.setState({indexImage: 0});
      }

      this.setState({loginBg: images[this.state.indexImage]});
  }


  componentDidMount() {
      this.timer = setInterval(
          () => this.changingBackground(),
          2000
      );
  }

  componentWillUnmount(){
      clearInterval(this.timer);
  }
}
about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda