Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

157
Vistas
How to filter array key by another array number key

I have 2 array, first array structure is:

items: [
    {
      name: "a",
      items: [
         { name: "jack" },
         { name: "jose" },
      ]
    },
    {
      name: "b",
      items: [
         { name: "lara" },
         { name: "jo" },
      ]
    },
    {
      name: "c",
      items: [
         { name: "andy" },
         { name: "hary" },
      ]
    }
]

and the second array:

number: [
  0: [0, 1],
  1: [1],
  2: [0]
]

How to filter "items" by "number" and How can such an output be obtained? (the best solution)

{["jack", "jole"],["jo"],["andy"]}
about 4 years ago · Juan Pablo Isaza
2 Respuestas
Responde la pregunta

0

A few maps would do it:

the output you wish is not valid JS so I made a nested array

const arr1 = [{ name: "a", items: [{ name: "jack" }, { name: "jose" }, ] }, { name: "b", items: [{ name: "lara" }, { name: "jo" }, ] }, { name: "c", items: [{ name: "andy" }, { name: "hary" }, ] } ], numbers = [ [0, 1], [1], [0] ]; 

const res = numbers
  .map((arr, i) => arr
    .map(key => arr1[i].items[key].name)
  )
console.log(res)

about 4 years ago · Juan Pablo Isaza Denunciar

0

If your number variable has to be an Object.

let items = [
  {
    name: "a",
    items: [{ name: "jack" }, { name: "jose" }]
  },
  {
    name: "b",
    items: [{ name: "lara" }, { name: "jo" }]
  },
  {
    name: "c",
    items: [{ name: "andy" }, { name: "hary" }]
  }
];

let number = {
  0: [0, 1],
  1: [1],
  2: [0]
};

let result = []
for (const [key, value] of Object.entries(number)){
  let names = []
  value.forEach(value => {
    names.push(items[key].items[value].name)
  })
  result.push(names)
}

console.log(result)

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda