Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

282
Vistas
Laravel Submitting form with same input name ajax

I need help with my ajax function. I have a form that submits data with the same input name

When I run my code without javascript, I can insert multiple input data with the same name,

Submitted structure

{"_token":"CepbQkKwKziSRwDJKuqlEa5i4E21Y5jvSbmDNvqu","id":"7","service_name":["asfd","safd"]}

When I implement javascript, a concatenated string is sent to the controller and this makes the service_name inaccessible.

formdata:"_token=CepbQkKwKziSRwDJKuqlEa5i4E21Y5jvSbmDNvqu&id=7&service_name%5B%5D=sdfg&service_name%5B%5D=gfds&_token=CepbQkKwKziSRwDJKuqlEa5i4E21Y5jvSbmDNvqu&id=8&_token=CepbQkKwKziSRwDJKuqlEa5i4E21Y5jvSbmDNvqu&id=9&_token=CepbQkKwKziSRwDJKuqlEa5i4E21Y5jvSbmDNvqu&id=10&_token=CepbQkKwKziSRwDJKuqlEa5i4E21Y5jvSbmDNvqu&id=11&_token=CepbQkKwKziSRwDJKuqlEa5i4E21Y5jvSbmDNvqu&id=18"

My javascript function

jQuery("form.ajax").on("submit", function (e) {
  e.preventDefault();
  jQuery.ajax({
    url: "/admin/adminpanel/insertService/",
    type: "post",
    data: {
      formdata: $(".ajax#servicesForm").serialize()
    },
    dataType: "JSON",
    success: function (response) {
      console.log(response);
    },
    error: function (jqXHR, exception) {
      var msg = "";
      if (jqXHR.status === 0) {
        msg = "Not connect.\n Verify Network.";
      } else if (jqXHR.status === 404) {
        msg = "Requested page not found. [404]";
      } else if (jqXHR.status === 500) {
        msg = "Internal Server Error [500].";
      } else if (exception === "parsererror") {
        msg = "function Requested JSON parse failed.";
      } else if (exception === "timeout") {
        msg = "Time out error.";
      } else if (exception === "abort") {
        msg = "Ajax request aborted.";
      } else {
        msg = "Uncaught Error.\n" + jqXHR.responseText;
      }
    }
  });
});

My PHP Controller Function

public function insert(Request $request)
        {
    
             return response()->json($request);
    }
about 4 years ago · Juan Pablo Isaza
2 Respuestas
Responde la pregunta

0

use FormData Object, to send fromdata

fd = new FormData();

fd.append("input-name", value1);
fd.append("input-name2", value2 OR arry of value);


jQuery.ajax({
url: "/admin/adminpanel/insertService/",
type: "post",
data: {
  formdata: fd
}
about 4 years ago · Juan Pablo Isaza Denunciar

0

I found a workaround:

First, I created an array, and pushed all instances of input[name='service_name[]'] into the array.

Then I passed the data with ajax and was able to insert the data.

var serviceArray = new Array(), id;
jQuery.map($("input[name='service_name[]']"), function(obj, index) {
    serviceArray.push($(obj).val());
});

My ajax script then:

jQuery.ajax({
    url: "/admin/adminpanel/insertService/",
    type: 'post',
    data: {
        'service_name': serviceArray,
        'id': id
    },
    dataType: 'JSON',
    success: function(response) {
        console.log(response);
    }
});
about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda