Say I have two arrays of objects
arrayOne = [{revision: { id: 1 }}, {revision: { id: 2 }}, {revision: { id: 3 }}, {revision: { id: 4 }}]
arrayTwo = [{someOtherProp: { id: 2 }}, {someOtherProp: { id: 4 }}]
How do I check the ids in arrayTwo against ids in arrayOne and returns the result index of the similar id occurrences like so [1, 3] (based on arrayOne we can see on index 1 and index 3 have ids that occur in arrayTwo)
This should work
arrayOne = [{revision: { id: 1 }}, {revision: { id: 2 }}, {revision: { id: 3 }}, {revision: { id: 4 }},{revision: { id: 5 }}];
arrayTwo = [{someOtherProp: { id: 2 }}, {someOtherProp: { id: 4 }}];
console.log(arrayOne.filter(o1 => arrayTwo.some(o2 => o1.revision.id === o2.someOtherProp.id)).map(x => arrayOne.findIndex(y => y.revision.id === x.revision.id))); // [1, 3]
This should work for your case:
one = [{revision: { id: 1 }}, {revision: { id: 2 }}, {revision: { id: 3 }}, {revision: { id: 4 }}]
two = [{someOtherProp: { id: 2 }}, {someOtherProp: { id: 4 }}]
for(let i in two) {
for(let j in one) {
if(two[i]['someOtherProp']['id']==one[j]['revision']['id']){
console.log(i,j)
}
}
}
You can use this implement:
arrayOne = [{revision: { id: 1 }}, {revision: { id: 2 }}, {revision: { id: 3 }}, {revision: { id: 4 }},{revision: { id: 5 }}];
arrayTwo = [{someOtherProp: { id: 2 }}, {someOtherProp: { id: 4 }}];
arrayTwo.map(v=>{return v['someOtherProp']['id']}).map(v=>{
return arrayOne.map(v=>{return v['revision']['id']}).indexOf(v)
})