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If else on array but only run the else statement once, not every time the return is false

I have an array and a name

var name = "Karen"

var arr = [ 
"Karen",
"Ronald",
"Mcdonald"
];

// Code here

I want to check if name is indexed in arr.
If it is then console.log(true) but if not I only want to console.log(false); one time.
I'm logging false every time the name doesn't match that is my problem.

about 4 years ago · Juan Pablo Isaza

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Answer 1 · 2022-07-10T17:42:00.303Z

It seems simple enough.

const name = "Karen"

var arr = [
"Karen",
"Ronald",
"Mcdonald"
];
if (arr.indexOf(name) > -1) {
  console.log(true);
} else {
  console.log(false);
}

Or Array.prototype.some:

var name = "Karen";

var arr = [
"Karen",
"Ronald",
"Mcdonald"
];
console.log(arr.some(n => n == name))

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If else on array but only run the else statement once, not every time the return is false

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