I have a gulp task that needs to read a file into a variable, and then use its content as input for a different function that runs on the files in the pipe. How do I do that?
Example psuedo-psuedo-code
gulp.task('doSometing', function() {
var fileContent=getFileContent("path/to/file.something"); //How?
return gulp.src(dirs.src + '/templates/*.html')
.pipe(myFunction(fileContent))
.pipe(gulp.dest('destination/path));
});
Thargor pointed me out in the right direction:
gulp.task('doSomething', function() {
var fileContent = fs.readFileSync("path/to/file.something", "utf8");
return gulp.src(dirs.src + '/templates/*.html')
.pipe(myFunction(fileContent))
.pipe(gulp.dest('destination/path'));
});
Is this what you're looking for?
fs = require("fs"),
gulp.task('doSometing', function() {
return gulp.src(dirs.src + '/templates/*.html')
.pipe(fs.readFile("path/to/file.something", "utf-8", function(err, _data) {
//do something with your data
}))
.pipe(gulp.dest('destination/path'));
});