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How to add traffic ID's to multiple different links?

I'm not a coder, but I know this should not be too hard.

Currently I'm running this script on my site to track where the traffic is coming from when they purchase through the affiliate links on my website:

 <script>
function getQueryVariable(variable)
{
       var query = window.location.search.substring(1);
       var vars = query.split("&");
       for (var i=0;i<vars.length;i++) {
               var pair = vars[i].split("=");
               if(pair[0] == variable){return pair[1];}
       }
       return("");
}

window.onload = function(){
    var anchors = document.querySelectorAll('a[href*="https://example.com/c/215029/222"]');
    Array.prototype.forEach.call(anchors, function (element, index) {
    element.href = "https://example.com/c/215029/222/?tid=" + getQueryVariable("tid");
});
}
</script> 

When someone visits my site with this url https://mywebsite.com/tid=facebook the above script is changing the specific link on my website to https://example.com/c/215029/222/?tid=facebook

My question is how to change the code so that it can change multiple links on my website to accept /?tid=facebook when I add /?tid=facebook at the end of the visitors url?

Let's say I also have a second link on my website https://example.com/c/215029/example2 that needs to adapt the /?tid=facebook so that it becomes https://example.com/c/215029/example2/?tid=facebook

What needs to be changed in the code above to make this work?

I hope I explained correctly

about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

Consider the logic of the following example:

function setUrlQuery(link, params)
{
  console.log("[setUrlQuery]: INPUT URL # ", link);
  const url = new URL(String(link));
  const se = new URLSearchParams(url.search);
  for (const [key, val] of Object.entries(params)) {
    se.set(key, val);
  }
  url.search = se.toString();
  return url.toString();
}

function delUrlQueryParam(link, ...par)
{
   console.log("[delUrlQueryParam]: INPUT URL # ", link);
   const url = new URL(String(link))
   const se = new URLSearchParams(url.search);
   if (par.length > 0) {
      par.forEach((val) => se.delete(String(val)));
   }
   url.search = se.toString();
   return url.toString();
  }

// set new parametres if not exists
const result = setUrlQuery("https://example.com/c/215029/example2/", {
  foo: "123",
  baz: "false"
});
console.log("[setUrlQuery]: RESULT # ", result);

// Update an existing values in the url query string.
const result_2 = setUrlQuery(result, {
  tid: "facebook",
  foo: "0",
  baz: "true"
});
console.log("[setUrlQuery]: RESULT # ", result_2);

// Delete an existing values
const result_3 = delUrlQueryParam(result_2, "foo", "baz");
console.log("[delUrlQueryParam]: RESULT # ", result_3);

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

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