Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

161
Vistas
Why is async request with await not waiting for the response data?

im not sure why await is not working for me, can someone help me out? I followed some guides and copied it exactly the same but still won't work. I need CardsID array to be filled before calling console.log(CardsID.length)

code:

  "[LL_REPTAG_URLPREFIXFULL /]/api/v2/businessworkspaces?where_workspace_type_id=54";

async function postData() {
  let response = await fetch(url, {
    method: "GET", // *GET, POST, PUT, DELETE, etc.

    headers: {
      "Content-Type": "application/json",
      OTCSTicket: "[LL_REPTAG_OTCSTICKET /]",
    },

    //body: JSON.stringify(data) // body data type must match "Content-Type" header
  });

  return await response.json();
}

//(async function(){

postData().then(function (data) {
  // Log the data to the console
  // You would do something with both sets of data here
  //console.log(data);

  data.results.forEach((element) => {
    CardsID.push(element.data.properties.id);
    console.log("added");
  });
});
//})();

console.log(CardsID.length);
console.log(CardsID);```

result (console):

0
[]
[]
[]
24 added


about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

You are calling the console.logs immediately after the postData() call, which is async (well, promise) and therefore won't wait for the execution to finish. Either you need to place the console.logs inside the then handler, like this:

postData().then(function (data) {
  data.results.forEach((element) => {
    CardsID.push(element.data.properties.id);
    console.log("added");
  });

  console.log(CardsID.length);
  console.log(CardsID);
});

Or (for the sake of consistency), you could make it all async/await, eg.:

async function postData() {
  const response = await fetch(url, {
    method: "GET", // *GET, POST, PUT, DELETE, etc.
    headers: {
      "Content-Type": "application/json",
      OTCSTicket: "[LL_REPTAG_OTCSTICKET /]",
    },
  });
  return await response.json();
}

async function run() {
  const data = await postData();

  const CardsID = [];
  for (const element of data.results) {
    CardID.push(element.data.properties.id);
    console.log("added");
  }

  console.log(CardsID.length);
  console.log(CardsID);
}

run();
about 4 years ago · Juan Pablo Isaza Denunciar

0

The problem is that code in the postData().then block is executed asynchronously, after the promise get resolved. The console.log(CardsID.length) statement will run before the then block get executed.

To fix that, you can run the console.log statement in the promise callback.

postData().then(function (data) {

  data.results.forEach((element) => {
    CardsID.push(element.data.properties.id);
    console.log("added");
  });

  // move the console.log statement here
  console.log(CardsID.length);
  console.log(CardsID);
});
about 4 years ago · Juan Pablo Isaza Denunciar

0

Just remember that your code below the .then block will run before it resolves because Javascript waits to resolve but continues through its synchronous run to execute the code below the any asynchronous code.

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda