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VistasHow do I remove a certain parent node in Firebase based on a child Cloud functions
I currently have my DB structure like this 
What I want to do is be able to loop thorugh each one that has a certain feedId, I've been trying it this way but am currently having no luck. Would anyone be able to assist?
function clearAllPostsInOwnFeed(userId) {
return admin
.database()
.ref(constants.FBC_USERS_FEEDS + '/' + userId)
.once('value')
.then((snapshot) => {
snapshot.forEach((snap) => {
if (snap.child('fromId').val() === userId) return snap.remove()
return snap
})
console.log(snapshot)
return snapshot
})
}
·
Juan Pablo Isaza
1 Respuestas
Responde la pregunta0
You're currently returning a snapshot from the inner callback. Since that is not a promise, it resolves right away - and your function gets terminated. before it has deleted the nodes.
The simplest fix is to use Promise.all() to wait for all deletes to finish:
function clearAllPostsInOwnFeed(userId) {
return admin
.database()
.ref(constants.FBC_USERS_FEEDS + '/' + userId)
.once('value')
.then((snapshot) => {
let promises = []
snapshot.forEach((snap) => {
if (snap.child('fromId').val() === userId) {
promises.push(snap.ref.remove())
}
})
return Promise.all(promises);
})
}
Alternatively you can use a multi-path update to wipe all matching nodes with a single write:
function clearAllPostsInOwnFeed(userId) {
const ref = admin
.database()
.ref(constants.FBC_USERS_FEEDS + '/' + userId);
return ref
.once('value')
.then((snapshot) => {
let updates = {};
snapshot.forEach((snap) => {
if (snap.child('fromId').val() === userId) {
updates[snap.key] = null;
}
})
return ref.update(updates);
})
}
·
Juan Pablo Isaza
Denunciar
Responde la pregunta