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I am trying to write a function that takes n numbers of integer parameters and return the products of all the arguments

Here is my implementation

function multiplyAll(a, b, c){
    return a*b*c
}

This is working, but imagine we have 10 arguments, or in a case whereby we don't even know the number of arguments that will be supplied? this is exactly what I want to achieve. Thanks

about 4 years ago · Juan Pablo Isaza

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Answer 1 · 2022-07-11T06:40:59.041Z

A simple and "clean" way to do it is by using an array as parameter of the function. Like so :

function foo(args) {
  let res = 1;
  for(let i = 0; i < args.length; i++){
    res = res * args[i];
  }
  return res;
}
console.log(foo([2,3,4]))

Answer 2 · 2022-07-11T06:40:59.048Z

You can use arguments like:

function argumentsFunction(a,b,c,d){
  console.log(arguments); // Object of arguments
}
argumentsFunction(1,2,3,4)

Reference:

arguments

Answer 3 · 2022-07-11T06:40:59.054Z

In ES6 you can now use the spread operator in function parameters. You can use the following code to achieve your goal

function add(...numbers) {
  let total = 0;
  for (const number of numbers) { 
    total += number;
   }
  return total;
}

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119

I am trying to write a function that takes n numbers of integer parameters and return the products of all the arguments

3 Respuestas

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