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How to achieve stratified K fold splitting for arbitrary number of categorical variables?

I have a dataframe of the form, df:

    cat_var_1    cat_var_2     num_var_1
0    Orange       Monkey         34
1    Banana        Cat           56
2    Orange        Dog           22
3    Banana       Monkey          6
..

Suppose the possible values of cat_var_1 in the dataset have the ratios- ['Orange': 0.6, 'Banana': 0.4] and the possible values of cat_var_2 have the ratios ['Monkey': 0.2, 'Cat': 0.7, 'Dog': 0.1].

How to I split the data into train, test and validation sets (60:20:20 split) such that the ratios of the categorical variables remain preserved? In practice, these variables can be of any number, not just two. Also, clearly, the exact ratios may never be achieved in practice, but we would like it to be as near as possible.

I have looked into the StratifiedKFold method from sklearn described here: how to split a dataset into training and validation set keeping ratio between classes? but this is restricted to evaluating on the basis of one categorical variable only.

Additionally, I would be grateful if you could provide the complexity of the solution you achieve.

over 4 years ago · Santiago Trujillo
1 Respuestas
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0

You can pass df.cat_var_1+ "_" + df.cat_var_2 to argument y of StratifiedShuffleSplit.split():

But here is a method that use DataFrame.groupby:

import pandas as pd
import numpy as np

nrows = 10000
p1 = {'Orange': 0.6, 'Banana': 0.4}
p2 = {'Monkey': 0.2, 'Cat': 0.7, 'Dog': 0.1}

c1 = [key for key, val in p1.items() for i in range(int(nrows * val))]
c2 = [key for key, val in p2.items() for i in range(int(nrows * val))]
random.shuffle(c1)
random.shuffle(c2)

df = pd.DataFrame({"c1":c1, "c2":c2, "val":np.random.randint(0, 100, nrows)})

index = []
for key, idx in df.groupby(["c1", "c2"]).groups.items():
    arr = idx.values.copy()
    np.random.shuffle(arr)
    p1 = int(0.6 * len(arr))
    p2 = int(0.8 * len(arr))
    index.append(np.split(arr, [p1, p2]))

idx_train, idx_test, idx_validate = list(map(np.concatenate, zip(*index)))
over 4 years ago · Santiago Trujillo Denunciar
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