I have an object with the following structure:
let obj = {
"foo": ["orange", "apple", "pear", "grape", "lime"],
"bar": [12, 6, 18, 3, 22],
"bat": ["a", "b", "c", "d", "e"]
};
I want to sort by bar but also retain the order of foo and bat relative to bar, like so:
obj = {
"foo": ["grape", "apple", "orange", "pear", "lime"],
"bar": [3, 6, 12, 18, 22],
"bat": ["d", "b", "a", "c", "e"]
};
Is there a tidy way to do this, or do I need to convert it to an array of arrays, sort by index (e.g., arr.sort((a,b) => a[1] - b[1]);), and convert back to the object?
const obj = {
"foo": ["orange", "apple", "pear", "grape", "lime"],
"bar": [12, 6, 18, 3, 22],
"bat": ["a", "b", "c", "d", "e"]
};
// get original indices of sorted bar
const indices = obj.bar
.map((value, index) => ({ value, index }))
.sort(({ value: a }, { value: b }) => a - b)
.map(({ index }) => index);
// iterate over obj's values to reorder according to indices
const res =
Object.entries(obj)
.reduce((acc, [key, value]) => ({ ...acc, [key]: indices.map(i => value[i]) }), {});
console.log(res);You can create a temp array base on all values. Then you can sort that array based on bar. Once sorted, Just fill data to new response while iterating.
const obj = {
foo: ["orange", "apple", "pear", "grape", "lime"],
bar: [12, 6, 18, 3, 22],
bat: ["a", "b", "c", "d", "e"],
};
const arr = obj.bar
.map((bar, index) => ({
bar,
index,
}))
.sort((x, y) => x.bar - y.bar);
console.log(arr);
const res = arr.reduce(
(map, { bar, index }, i) => {
map.bar[i] = bar;
map.foo[i] = obj.foo[index];
map.bat[i] = obj.bat[index];
return map;
},
{ foo: [], bar: [], bat: [] }
);
console.log(res);