You could use 2 capture groups:

\bPrice Our: (\d+(?:\.\d+)?) => (\d+(?:\.\d+)?) \|

The pattern matches:

• \bPrice Our: A word boundary to prevent a partial match, then match Price Our:
• (\d+(?:\.\d+)?) Capture group 1, match a number with an optional decimal part
• => Match literally
• (\d+(?:\.\d+)?) Capture group 2, match a number with an optional decimal part
• \| Match |

Regex demo

const s = "Delivery: Price => 30.00 - 45.00 | Price Our: 1900.00 => 1800.00 | Delivery: Contact => 3 - 4 Days | ";
const regex = /\bPrice Our: (\d+(?:\.\d+)?) => (\d+(?:\.\d+)?) \|/;
const match = s.match(regex);

if (match) {
  console.log(match[1]);
  console.log(match[2]);
}

In case the digits are at the end of the string, and there is no | following, you can account for that using an alternation to assert the end of the string:

\bPrice Our: (\d+(?:\.\d+)?) => (\d+(?:\.\d+)?)(?: \||$)

Regex demo

(\d*\.\d+)

regex101 explanation:

const regex = /(\d*\.\d+)/gm;
const str = "Delivery: Contact => 3 - 4 Days | Price Our: 1900.00 => 1800.00 | Delivery: Contact => 3 - 4 Days | ";

const res = str.match(regex)

console.log(res)