Company logo
  • Empleos
  • Bootcamp
  • Acerca de nosotros
  • Para profesionales
    • Inicio
    • Empleos
    • Cursos y retos
    • Preguntas
    • Profesores
    • Bootcamp
  • Para empresas
    • Inicio
    • Nuestro proceso
    • Planes
    • Pruebas
    • Nómina
    • Blog
    • Comercial
    • Calculadora

0

39
Vistas
merge 2 array and replace same key using lodash

i have this 2 array,

const firstArray = [
{
 key: 'a',
 value: 'a'
},
{
 key: 'b',
 value: 'b'
},
{
 key: 'c',
 value: 'c'
}
]

const secondArray = [
{
 key: 'b',
 value: 'd'
},
{
 key: 'c',
 value: 'e'
}
]

i want to merge these 2 array, and if a same key found on second array the second array value will replace first array value

the new array should look like this

const expectedArray = [
{
 key: 'a',
 value: 'a'
},
{
 key: 'b',
 value: 'd'
},
{
 key: 'c',
 value: 'e'
}
]
7 months ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

As I see lodash in your tags, I assume you want to use it.

You can use something like this:

var merged = _(firstArray)
  .concat(secondArray)
  .groupBy("key")
  .map(_.spread(_.merge))
  .value();

It basically groups all objects with the same key into an array with groupBy("key"), then flattens out each array of values merging them and taking the last one with .map(_.spread(_.merge)).

I suggest commenting out the final likes and see all the intermediate steps if you want to fully understand the process, it's interesting!

const firstArray = [{
    key: 'a',
    value: 'a'
  },
  {
    key: 'b',
    value: 'b'
  },
  {
    key: 'c',
    value: 'c'
  }
]

const secondArray = [{
    key: 'b',
    value: 'd'
  },
  {
    key: 'c',
    value: 'e'
  }
]

var merged = _(firstArray)
  .concat(secondArray)
  .groupBy("key")
  .map(_.spread(_.merge))
  .value();

console.log(merged);
<script src="https://cdn.jsdelivr.net/lodash/4.13.1/lodash.min.js"></script>

7 months ago · Juan Pablo Isaza Denunciar

0

Solution without lodash is to iterate through the second array and just look for matches.

If there's no match, push the item to the first array.

If there's a match, replace the item in the first array with the one from the second array.

const mergedArray = [...firstArray]

secondArray.forEach(newItem => {
  const matchIndex = mergedArray.findIndex(prevItem => prevItem.key === newItem.key)

  if (matchIndex === -1) {
    mergedArray.push(newItem)
  } else {
    mergedArray[matchIndex] = newItem
  }
})
7 months ago · Juan Pablo Isaza Denunciar

0

const mergedArray = [...secondArray, ...firstArray];
const lengthOfUniqueArray = new Set(mergedArray.map((item) => item.key)).size;
const expectedArray = newArray.slice(0, lengthOfUniqueArray);

expectedArray will be what you want.

7 months ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos