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VistasName returning a number after serializing data
I have a table service :
from django.db import models
from users.models import CustomUser
SERVICE_CHOICES = (
('Carpenter', 'Carpenter'),
('Driver', 'Driver'),
('Ambulanve', 'Ambulanve'),
('Spa', 'Spa'),
('Barber', 'Barber'),
('Cleaning', 'Cleaning'),
('Cook', 'Cook'),
)
class Service(models.Model):
name = models.ForeignKey(CustomUser, on_delete=models.CASCADE, limit_choices_to={'is_worker': True},)
service = models.CharField(choices=SERVICE_CHOICES,max_length=100)
def __str__(self):
return f'{self.service} - {self.name}'
and a table CustomUser :
from django.db import models
from django.contrib.auth.models import AbstractUser
class CustomUser(AbstractUser):
is_worker = models.BooleanField(default=False)
is_customer = models.BooleanField(default=True)
I am serializing the Service table below :
from rest_framework import serializers
from django.contrib.auth.models import User
from .models import *
class ServiceSerializer(serializers.ModelSerializer):
class Meta:
model = Service
fields = '__all__'
But when I add a service from the admin panel, the name shows a number in the browser and not the string. How do I change it to show a the name and not a number?
·
Santiago Trujillo
2 Respuestas
Responde la pregunta0
In your ServiceSerializer you can try:
class ServiceSerializer(serializers.ModelSerializer):
class Meta:
model = Service
fields = '__all__'
def to_representation(self, instance):
rep = super(ServiceSerializer, self).to_representation(instance)
rep['name'] = instance.name.name # instance.name.what_you_use_in_Custom_User_model_to_represent_name
return rep
However, consider whether this is what you want, because this change could lead to more problems than it solves.
·
Santiago Trujillo
Denunciar
0
This is because name is a forignkey to CustomUser, and the default behavior is to return the PK related to the CustomUser instance.
Instead you could use SerializerMethodField.
class UserSerializer(serializers.ModelSerializer):
name = serializers.SerializerMethodField()
class Meta:
model = Service
fields = '__all__'
def get_name(self, obj):
return obj.name.first_name
·
Santiago Trujillo
Denunciar
Responde la pregunta